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Retired NBME 20 Answers

nbme20/Block 2/Question#41 (reveal difficulty score)
Purified serum antibodies elicited by ...
Proteins X and Y express the same epitopes 🔍 / 📺 / 🌳 / 📖
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 +11  upvote downvote
submitted by usmile1(154)
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If you ookl at wdorlU nioesqut DI 12299 ti has a nrfuweldo niapoltxaen orf isht. I f eyht rehas het esma petie,pos ti lliw ehva a wddnrawo olp If.se thye erhas enno of het esam psoetep,i teh ienl wlil be ilrozotnha ocasrs eht ahgrp (cindigtani no ancegh sa het ontaum of Y aeddd )easncreis

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eacv  ogm !YSE! hsktna lwrUdo I tgo ti crcreo!t ycaltex ihts xq askde hte caetx stooeppi !gitnh Hahaah I dlove it !! +9
pg32  evnE rfeat eniardg teh lUodWr iaato,nnlxep I am siltl not seur who eht esrawn ahtt adr,se "rtPoine Y sspeseexr lla of eht ptpeeois pesdsxree by ierntpo X, btu eipotnr X dseo n"o..t. is icrotecnr. sedBa no teh hr,gap I nt'od ese a ywa we nca urle tuo hatt naerws iohecc nad it sondsu omer iyekll tnah boht X adn Y nahvig het ATECX ESMA eppis.eto naC ayenon elpainx? thWa lwodu teh agrph oklo ekli if the doeutq wraens cioceh was ?rcorect +3
69_nbme_420  If you mkea up an pxemlae ihwt unsr,ebm ti learly epl!hs nroe“iPt Y rsespsxee lal fo hte eopiepts edeexsrsp yb X, tbu ptinroe X dose ont essrepx lal fo oipepest dexessrep by etoriPn .I fY” ew ays neirtop Y ash eoitsepp ,1 2, nad .3 nehT noPreti X sah setipope 1 adn .3 enTh we cna ecyrlla ees het oanelhstipir het UTNMOA fo Y daedd etreialv to X bunod owldu NOT eb eli.arn dtSate torhane way – ew ende na ntnylieaolpex mroe tuoamn fo Y to MELPTYEOCL niudbn X dna reethrefo trhee ldowu ont be a neo to one eidcntiop ni the agalhmriprSi ocigl iaplesp for eht swenar coceih that states repo"nti X sexeresps lla fo the pisepteo sdrxseeep yb tnripoe Y, btu pitrneo Y seod tno erxseps all of het stoeppie esdeesxpr yb eortpni g. .E.X If pireont Y ash estoeipp 1 dan 2. dnA ipnroet X sha epteipso ,1 ,2 dna 3. eeHr ina,ag ew vaeh asiedtfsi the ranswe eocshci notiod,inc dna on tterma owh umhc we enrecsai prieont Y, enirpot X liwl llsti vahe epoeitp 3 nbuod in hits cs.ea +5
69_nbme_420  utJs to ylaircf for hte fsirt sc:ionear eW evah 3 ppeeitos no Y, dna 2 eippotse no .X thTa ma,sne ssnmaigu het epeoistp era lal etsernp ni aeulq ,mnaotus if I add 003 mgras fo torpine Y to teh tnuisool - ynlo 020 smgar lwli inbd npeotri .X NAD YLON 020 asrgm fo oteipnr X nac be unobdun. Heop eth rnbusem !phel +1
fruitkebabs  rFo bdoayny ltlsi stkuc on Pno"reti Y epsesrsxe lla fo hte ietspeop dexpseser by ptrnoei ,X tbu epotirn X eods ,"otn alutohhg sith teesttmna aym eb erut, heret is tno eonguh iitfnamonro ni the unosiqte ot roepv s.tih eW ownk rof ctfa hatt cuesbae the uAtmno fo lebalde X udonb ecshaer ,0 ta het ryev eatl,s pinetro X dan Y perssex hte aesm steopeip icnse at a recntia c,tornnoaicent Y is labe ot pceoyllmet adpliecs lla X mrfo eth steym.s ihTs nedtso' cluexed eht bipoylstiis that hrete aym be taexr tpieesop on Y, ubt ti 'odtnse pvoer it iereth. +4


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 +2  upvote downvote
submitted by amarousis(27)
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os ohw luwod teh raphg ookl fro tniproe x erxspsees lal of eth siopptee sexrdeesp by rtieopn y, btu itrpoen y edso ont pssexre lla of teh iteseopp spsdeeerx yb tieonpr x?

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drw  hnte eoms aitX-n nnctao eceoltar ot Y eevn Y si eddda at hewtevar gihh d.oes ta isht n,cdonoiit the leni anc nreve cthuo eht as.Yi-x on hte ,rnyrctao if Y erpssex lal itpoeesp no teh X, tbu X dsoe not sxreesp all itepospe no eth Y, ttha amnse emos Y ieoseptp are tno enes no .X at sith icnoot,ind I 'odtn kown htwa ilwl eb teh neli deolok ik.el +1
medbound57  I tihnk ahtt teh 'lnsie wdnwroda elpso wduol be ,espetre nscie Y has erom estis atth the idtaoynb uwdlo dinb .to +

why this is wrong- prtoein y has all epitopes of x and protein x does not have some epitope


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 +1  upvote downvote
submitted by usmleboy(19)
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An oidynatb nac yoln nrcoezieg a ignlse .petepoi Siecn ew ese the rmeo Y dddae ldesa ot sesl X b,oudn tnhe uoy anc rasneo eyht shear hte esam ngiindb sset,i and Y is eivroongerwp .X

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srmtn  GMO stih si het asnreo wh!y tnakh oy!!!u +
srmtn  btu ereht aer nboedstaii ttah nac icetanrt whit 01 tmsxalpppeeo.i.e.e gM..I. oyrrs gto ltso giaan (: +
chj7  rFo oanyen ilstl dllgwnie on hsi,t the cporses eyth tlak abuot ni het tsounqie etms is lpisoybs pyoolanlcl (hstu the suies fo eimupllt p.epesti)o +


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submitted by rhizopusmucor(1)
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I ufndo ,iths I intkh it sigve inkda fo na naox:pintela If teh rsionreges of ogl (/('AA) 1-) on og-l B si iaenrl whit a poels of -1, nhte this tsneadcii atht het inamsgoatn si pomvitciete dna yb ndtiifieno eth oiagtsn adn tosgnaanti tca at hte SEAM necoingiort esist. oS lcayiabls teh mero yuo add Y, het sels X is nubod, whhic nsmea ehyt vaeh a eams uucslarttr ocenomnpt e)opp(tie nad usmt cta on het esma ets?i Dotn' ownk if siht eaksm .e.s.ens

bhsmjbynihlbat/h/n.ot/ud.uti~e/rauptsc:gdecppcfsamleio/s.d/s1ght

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 +0  upvote downvote
submitted by stepwarrior(29)
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siht tiuqsneo saw tetru B,S btu eht ayw I detsiiufj ma"se etopipe"s swa htat ti isda n"i hte cttnxoe of -rtmneiuas X," .ie., chihw epitoesp lduwo ahev been vpdedoeel ni the etnoxtc of eth biosdtiane ptners.e I'st lkulinye tath ian-tX ebnsidiato dowlu nbdi ot oestppei no Y atht enat'r on .X tuB uoy oucld auerg ehrte aer toeecitrahl opteeips no Y ttah ldcuo be onbud yb aorneth aoinbtdy ahtt 'tosnde xiets ni tsih ro.csanie

eyrV radwn tuo dan ktoo me 5 esniumt to utylcaal irfgue uto no hte t,set yolhsent a seatw of mtie in ym ,oipnino btu htere oyu .og

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submitted by peachespeaches(2)
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asceeBu ti is a thigrast wrwaodnd s,peol uyo can aslo eltl htta Y nda X ear dboun ni iasmrli ayws by nbiiotds.ea thaW frsnfiieeaettd eth wot, tenh, tns'i eitepop gnbniid ciyapabilt, tub eht tnnnocoir.ecat lAl slee aequl ihtw ibnndgi its,es erom Y ithw na nnhagignuc oautnm fo X llwi deal to ssel X nudob, in a 1:1 an.menr

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submitted by ilikecheese(46)
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gHhi X is dobnu nwhe lwo Y si ,dddea adn owl X is nubod hnew Y si dd.ae oSd AMEYB heyt aer cgnmitpeo ofr eth seam ngiibnd titope/oppse ued ot isth lnaiisopterh tp=eepoi( atinbydo inbdnig i???s??????e?)t

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submitted by breis(56)
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rouy ssgeu is sa oodg sa .............m..................e.........i.............n................

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nala_ula  I nspte so olgn on shti siutoneq and as..m.e ahhaah +


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submitted by am.cassandre(0)
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aRn srsaco a noutsieq miilras to tihs in roeahnt sonetiuq .knba nI atht isenq,uot rteeh asw on gcnhea as the nnoconrattiec of eht wne enopirt swa ,ddade hcihw menat atht eht tow trspeino idd ont rheas lirisma et.opsiep nI tish teniqso,u hte iboydtan is sjut tngriy ot dbni tis t,ppoeei os dnagdi mroe ro y easmn sles ndbgnii fo rtiopen x cseueba teh ndytaibo fsvaor het eoirnspt het mes.a

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This question tests the basis of competitive inhibition. if they express the same epitope, they will bind the same receptors. Adding more X will mean less binding of Y, hence the downward slope.


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