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Retired NBME 20 Answers

nbme20/Block 2/Question#41 (reveal difficulty score)
Purified serum antibodies elicited by ...
Proteins X and Y express the same epitopes 🔍 / 📺 / 🌳 / 📖
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submitted by usmile1(154)
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If oyu okol ta rwdloU nqeustio ID 19229 ti ash a efnwrdolu aanxnoiltep rfo sit.h I f tyeh arhes eht aems topee,ips ti llwi hvae a wdarnowd e.oplsIf ehyt rehsa onne of eht msea ep,sipote hte enil will be ztalhoinro ssrcao het arhpg angdnii(tic on chegan sa het umonta of Y daded c)iesersna

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eacv  ogm YE!!S skhnta wlUdor I otg it orcce!tr xeactly itsh xq eskda the caetx eitppsoo it!hng haahHa I oldev ti !! +9
pg32  veEn tarfe darieng het rUdloW eailnxpnat,o I ma lstil nto eurs ohw eth arwens tath asder, ntP"eiro Y sersepexs all of the tpoeesip pdxseesre yb erpiont ,X ubt orpenit X dose t"on... is tcnreoc.ir seadB on het pag,hr I o'ntd ees a wya ew nca ulre otu ttah rswena ecchio adn ti dsosnu orem ikylel hnat ohbt X and Y avhign eht CXEAT SAEM sep.teiop aCn neoayn nialxe?p htWa douwl hte rgpah loko kiel fi hte dutqoe wnsera choiec saw ?tercroc +3
69_nbme_420  If uyo kame pu an elempxa ihwt smre,nub it lrleya s!elph retPo“ni Y rpeexsses all fo teh teopepsi sxsedpeer yb X, utb oritnep X deso ton spreexs lla fo etsieopp edpesexsr by Preiont Yf I.” ew yas iprnoet Y sah tpeoesip ,1 ,2 nad 3. heTn oetnirP X sha episoetp 1 dan .3 nehT we cna caelylr ese het ltpihrnieoas eht NUATOM of Y dedad lreetaiv ot X onbud duwlo ONT be rilane. Sttaed aotrhen wya – ew nede an enxltpiayleno orem moutan of Y ot LTECYPOEML indbun X nda eorerhtfe trhee udolw ont be a eon ot eon tdpocneii in hte Smapiira ghlr cliog ipelpas fro the sawnre chcieo that astset r"oietnp X pxerseses lal of eth topisepe dsxeepsre by pneroti Y, btu ornepit Y eods nto sxersep lla fo teh petiespo exsesrped yb oineptr ..X.gE fI npiteor Y sah ptoeespi 1 dan .2 ndA ptinore X hsa oseetipp ,1 ,2 nda 3. ereH n,agia we aehv saiisedft eth wanres eicchos indn,tcooi dna on mrtate woh cmuh ew nracseie treoipn Y, nietpor X liwl ltsli veha opetepi 3 udbon ni itsh eac.s +5
69_nbme_420  stuJ ot ilyarfc rof teh trsfi a:conseri eW ahve 3 petopsei no ,Y dan 2 sopeietp on .X tTah aens,m guniassm eht speptieo era lla sepnrte in elaqu ,umsoatn fi I dad 003 gsmra of trnopie Y ot hte oustnoil - lnyo 020 rgasm lwli dbin tpeoinr X. ADN OYNL 020 rgmsa fo pierotn X nca eb nudobn.u epoH het nemsubr hpel! +1
fruitkebabs  roF oaynybd tlsli custk on oeiPn"rt Y exspersse lal fo the oisppete epssedrxe yb tperoin ,X ubt tronpei X osed "tno, tahugloh thsi atesnemtt aym eb rue,t three si ton eghnuo ointnrfomia ni eht sqteiuno ot ovper hsit. eW kwon fro afct atht eebuasc het nmuAot fo ldeabel X bdnou earcseh 0, at the ervy satl,e peroint X nda Y ssprexe eht mesa psepiote sienc at a taenric ontno,canetirc Y si labe to otlemplcye elicaspd all X omrf teh s.teysm shTi stone'd cueldex the bpoystiisli ttah hrete amy eb txaer soeiptep no ,Y tbu it tnosd'e eorpv ti .ierhte +4


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 +2  upvote downvote
submitted by amarousis(27)
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os hwo odluw het gaprh oolk for npteior x rexepssse lal fo eth epsteoip speexrsed yb orntpei y, but erpoint y eods not ssxrpee all of het oetpeisp repdsxsee yb eonpirt x?

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drw  nhet soem iaXtn- ntaonc teelocar to Y even Y si deadd ta wveatrhe gihh .deso ta hsti oidnnoi,ct hte line acn evren ochtu teh xYsi-a. no eht ocynrtra, fi Y erespsx all tiopspee on het X, but X eods tno sprexes lla oespepti on hte Y, atth mnsae mose Y sioetppe aer tno esne no .X ta htsi onctind,oi I o'ntd nowk htaw lwli be eht line lkoedo ki.el +1
medbound57  I kithn ahtt eht nlie's rnowawdd seolp wudlo eb r,eepets csnei Y has reom sstie that the dbytiaon wdolu bndi .ot +

why this is wrong- prtoein y has all epitopes of x and protein x does not have some epitope


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 +1  upvote downvote
submitted by usmleboy(19)
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An tondbiay cna ylon onergiecz a eislgn pit.peeo eScin we ese eht rome Y deadd slade ot sels X n,odub nhte uoy nca rneosa teyh ehsra hte seam ndiginb ,itsse dan Y si wiogeponvrer X.

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srmtn  MGO sthi is eth oreasn !yhw ankht !!oy!u +
srmtn  ubt rethe rae ebitinsdao taht can nittreca hitw 01 eep..xiospplte.eam gI...M roysr tgo otsl iagan :( +
chj7  rFo nneoay sitll neldgliw on ,thsi hte psrocse etyh alkt tuboa in eht ouqtsnie tsme is bsyiolps alynlcpool (tuhs the iesus fo ulmpteli s)ippt.eeo +


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submitted by rhizopusmucor(1)
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I nduof ,siht I ithnk it geisv nakid fo na ltxnianpe:ao If eth issrgoeern of glo A(A/'() )1- on -ogl B is lnarie twhi a ploes of -1, nteh htis aistincde ahtt het smatngiano is otmciptevei adn by ntdnifieoi eht stgiaon nad iogtasantn cat ta eht EMSA icornoiengt stise. So acilalybs the more ouy add ,Y het elss X is b,undo chiwh nsmae hyet vhae a maes srulcratut nmceoptno ete(pio)p dan smut tca on het emsa iest? tDno' nwko fi tihs asemk ne.e.ss.

yarb:nh/i/nucpiolbgts1.js/usotcthddp.mlhs~ctpaeegbhu.ds/eaif/tm/

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submitted by stepwarrior(29)
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isth ioqneuts swa euttr ,SB utb hte ywa I fujdeiits emsa" se"oetpip was htat it isad in" teh nttceox of a-seumrnti ",X .ei., hcwhi pespoiet odluw eahv eenb dlepodeve ni eht tnoctex of eth tdiaiobsne rt.npees s'tI nileuylk atht tia-nX ndaosbeiti udolw ibdn ot seoeptpi no Y htat erta'n on .X But uyo uocdl gruae trehe rea rihtcoeltea isopeept no Y atth olcud be nudbo yb eaothrn ydnaitbo that oed'snt seitx in htsi o.csrnaei

Vyre awrnd out adn okot me 5 semintu to alaytlcu igrufe tuo on eth test, nhyolest a wsate of miet ni ym ,innioop tub heret ouy og.

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submitted by peachespeaches(2)
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Bceuase it si a attigrsh nawrddow eo,lsp uoy nca lsoa tell atht Y adn X ear bunod ni irmsali syaw by iod.nisbeat athW aesniffetriedt teh ,tow ehtn, t'nis ppetoei nbdingi ay,tlbaicip tbu hte iacntncoorn.et All lsee euaql ihwt dginnbi ei,tss rome Y tihw an nggnicaunh ntmoau of X lliw dael to elss X bond,u in a :11 merna.n

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submitted by ilikecheese(46)
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ighH X is obund nweh olw Y is eaddd, adn wlo X si ubnod hwne Y is dad. doeS YBEAM ethy rae pmitgcoen rof the emsa igdbnni ooppttsie/ep edu to htsi iernipolhtas =eptieop( yondiatb bndinig e?t??s??)?i ????

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submitted by breis(56)
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yuro gsuse is sa good as ..............i.e..................................n....m................

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nala_ula  I tpnes os long on sthi intuqeos adn a.me..s aahhah +


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submitted by am.cassandre(0)
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Ran scsroa a niqtesou ilirmsa to shit ni otanreh ieoqtusn .nbak In ahtt niqoe,uts eethr aws no gehanc sa hte nerontnccaoit of hte wen oenprit wsa ddaed, hihwc matne ttha eth tow erotnsip did not erhsa iailmrs tpeep.ios In ihst n,uiostqe the bydntoai is tsju rtinyg ot nbid tsi i,eotppe os agdidn meor ro y emsna less nidnigb fo optiren x ecsbeau eht badynoit fsrvoa eht irspneto the sam.e

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This question tests the basis of competitive inhibition. if they express the same epitope, they will bind the same receptors. Adding more X will mean less binding of Y, hence the downward slope.


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