aneMlinda eist:ecGn
anM has 3/2 cnhaec fo nbegi a crair.er e(H esod otn aevh teh ed)saesi. onamW cirarre rksi tsmu eb tecldcaalu htiw 2^p + q2p + q2^. ^2 q = 14/000,0 q = ,021/0 p si orhgylu = p 2q1 = /1100 = Cearrri ceqnfryeu .
kiRs fo givhan a hcidl usht lsueqa /23 x 0/011 x /14 = 0/610/c s:Be e2u3a = nMa aCreirr krsi 10/1 0 = alemeF eriCrar isk41 /R = Cncahe heyt ceah spas on het esecesivr enge to tehir .goirspnff
hTis het mase sa py'emckson@ya pnnxaoailte hitw roem oatpilaennx tohse hatt ndee .it..
eTh tpteain is ncffetduea yb teh priarcualt aaolsmout svereisec aseeids dan sih rbertoh has het sutaoalom seesciver ediesas &-;gt- sthi anems eahc fo irthe asetnpr rersica hte AR a.eelll oN,w rof hte ntatpie to be ncdetueaff inevg that tboh shi nratpes hvea het RA eallle, ti aenms htta the tpatine sah a 23/ nceahc atht eh si lunmtoyuiselas fuefaecdtn adn a acrrri.e
Teh i'aesttnp teanprr si ucaefetndf dan nmaorl eHga-erbynWrdi scingete a(s sadtet ni eht hnw.eemlbrp)o. thsi si lpfilcsyciae ,oeetnmidn you rae to aessum ttha het rraeptn has a rraecir recnfqyeu rfo het RA ,laelel cwhhi qelua ot 2p.q
heT sdaiese hsa a fuenyceqr ni eht ointpaopul fo 4/001.00 ishT si q2^ ;&-g-t ^2q = 00.1040/ olgviSn orf q, you teg q = 00./12
reCarir ecyrnfque is q2.p Hevower, rfo a raer es,saeid p2q ≈ 2.q oS, hte crreria quncfyeer orf het rretpna = q2 = 2 * /1200 = 1./001
,wNo teh Q akss auobt an gffrpsnio of the tpeinta dan hsi ptraren nigbe eefctafd, os ot heva na etdfcfea lhicd, ehert si a 1/4 nhecca fo vhnaig na defetcaf hidlc e(suebacs eth pttaien dan eth tarrnep tboh aevh a /21 hacenc fo gisnpas het eealll &t;g-- uoy umlilpet seeht gerhotte 1/2 * 21)/.
,oS pulytlim /23 * 1001/ * /41 = 60/1.0 siTh is tP(itpean bnieg a arer)cri * Pnart(erp ngibe a rcrai)er * vhgPna(i an eadctffe irsfpgnfo erhg.tt)oe
hTe iarblotbipy of hte ftehra bgien a rcierra is 32/ ecins it si wnkno ahtt he e’stond veha eth seed.sai Tnhe hte pirlyaobibt of hmi sasignp it on ot ihs dik si:
2/1 * 3/2 = 3/1
hWit the birHradneW-gey pin,cePirl uoy nac eiurgf otu hte tirailpboyb fo hte ethmro nbgie a ia:rrrce
q = )4q000,/(r10ts = 1002/
o,S q2p = 2 * /2010 * 0/99210, hwhic rpopxa si 00,11/ dna het obbyliaritp of the cdilh tteggin hist lealel is 0011/ * 2/1 = 2001/
T:hus
001/2 * /31 = 0106/
wyh rteeh is ibpyrliabot of fheatr egbni a aericrr is /32
We assume this is a recessive disease. In other words, you manifest the disease if you inherit a disease allele, d, from your mother and a disease allele, d, from your father (giving you the allele pairing denoted by “dd ”).
dd = you have the disease.
The father does not have the disease; this means his genotype cannot be dd and thus must be one of 3 things: DD, Dd, or dD.
That is,
Notice that in only two of these 3 possibilities (⅔) does the father (potentially) have a disease allele, d, that he might pass on to his progeny.
submitted by ∗drdoom(1206)
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$279$49iultlconCasa for add. eTh itabrplybio fo the thraef gbnei a arrrcei is /32 icens it si nknow thta he n’tdsoe vhae het e.daeiss Tenh eth iioayrlbbpt of ihm spnsgai it on ot shi kdi si 1/2, suth:
sticaluColna ofr mmo. iWth eht rrdgibaeyWHn-e rpePl,inci uoy cna ireguf uto the abyortiipbl fo teh ohetmr gbein a irrcea:r
q = s1t4(,00q0/)0r = 0/120S,o
2qp = 2 * 0/021 * 901/290, whchi si roappx /010.1oFr the hlicd ot tge eht ealell mrfo o,mm two gihstn edne to phpean: 1)( mmo tsmu be a icarrre ”te[hzgte“]oeyor dan )2( mom tsmu pass the lealle to d:hcil
tnuPig ti all rthetgoe. N,ow nmiecbo lla hoeetgtr:
= (btpaoiblyri fo dad gbein ricr)are * yibptoirla(b fo add ssapign on ideeass )llelae * oyrpiibat(bl fo mmo eingb )iaercrr * arpiob(tlbiy of mom snspgai on deaessi l)lalee
=
2/3 * 21/ * 0110/ * /12=
1 ni 060$279$49