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NBME 22 Answers

nbme22/Block 4/Question#4 (48.2 difficulty score)
A 24-year-old man who is comatose is admitted ...
25 mL/cm H2O🔍,📺

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submitted by alwaysanonymous(31),
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Hsi tilad moevul asw 050 m.L rtanoriyEd-exp was +5 mc and pisae-tdnoriryn saw 2.+5 eW erew seodsppu to esu het efecfindre in yiawra errsuspe, adn nto teh nirr-odsptyaeni ralelpu reeurpss .2()+0

nlompicaeC = PΔV/Δ = 500 / 02 = 25 /mLcm H2O

some-zheimers  Great explanation. In general, also a great idea to pay attention to the units. I studied Physics in undergrad and have got one or two questions based purely on following the units, when the formula slips. +23  
endochondral1  is that equation in FA? +  
redvelvet  yes @endochondral1, at page 651 in 2019FA +19  

submitted by menacingmegalodon(0),
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Hwo od uoy oknw thta yrsapeitorr etmssy lpcoienmca is 52 /mclm h2?o

alwaysanonymous  His tidal volume was 500 mL. End-expiratory was +5 cm and end-inspiratory was +25. We were supposed to use the difference in airway pressure, and not the end-inspiratory pleural pressure (+20). Compliance = ΔV/ΔP = 500 / 20 = 25 mL/cm H2O +6  
victorgaldos  this is dynamic compliance and the formula is = VT / (peak pressure - Peep) 500cc of H20 pressure / (peak pressure of 25 cm H20 pressure - 5 cm H20 pressure) = 25 cm H20 pressure. +