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Retired NBME 20 Answers

nbme20/Block 3/Question#1 (reveal difficulty score)
The frequency of an autosomal recessive ...
1/25 ๐Ÿ” / ๐Ÿ“บ / ๐ŸŒณ / ๐Ÿ“–
tags: biostats

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 +16  upvote downvote
submitted by jotajota94(14)
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sUe eht raeigbyHeWn-dr iquenota

  1. aeTk het seqaru roto of /11,060 adn ttah lliw vegi you the yefeqncur fo teh eeivrssce elelal = /041.
  2. cleCuaalt hte ycfrnueeq fo eth adotnnmi alleel hitw 1+,p=q icwhh is =p .07.59
  3. Teyh era inleltg uoy ot ucllaacte the cfqynuere fo teh seeisad rraeirc,s hhiwc is hwti teh iuaenqot q.p2
  4. hTey tnaw nylo eth disseae eracrsir in wchhi ltdnieeo si nt.rseep oT aetalulcc ,shit use eht q aulev 14)0(/ nda ltilmpyu by %80 in sthi hoduls vige oyu 00.2.
  5. ail,Fyln ealctcual ofr 2Pq2 (50()902.7.=0) .004 = 2/51.
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yex  i!cNe a.n.d. we are udspspeo ot rade hte mtes nad od all hist in a uenmit ro s?o :/- +28
charcot_bouchard  lelAle fyuecenqr 4/0.1 os eircrra ferq 02/1. %08 fo 1/20 si 15/2 /(10800 x /)102 +15
dickass  hA cke,f pq2 gto me +1
hello_planet  A hynad tuohrcts rfo -dyegnarriHbeW si thta uoy eyrelalgn acn aussem p ~= 1 if q fi ariyfl low. It osla dtsen ot be ersaie to rowk in trfnoicas if eht rnswae esicoch ear ni nafsotcri os you ton'd eahv to uoencb ackb dna rtohf ewntebe nsfaitcro dan ca.lmedis So thiw hatt, you esnd up twih p2q = 2 * 1 * 5/01 = 025/ = 52.1/ +9
topgunber  thea hsti ehwol elscarbm :tngih n I eno elni: 2 * q * 80shT%.i is orf sdiseeda idsaulvdini (wto q sleIell.a) = 610/01 = 2^heT q ceeyurnqf fo q = w1N0 /4o rrscreia is 2 p .q P si lseco to eno mnsuagsi HW eqm +=q.p(1) sThe'er an adioadiltn step in itsh ietusnqo eud to eth wto etifdrfen tos snmu.aiot (q)2 = /21.0 %80 of eseth esrirarc rea esotlidne os lmiuplty 1/20 * .08 = 152/ +

@usmlecrasher

1/40 = .025 = q P + q = 1 -> P + .025 = 1 -> P= 0.975

+3/- alexp1101(11)

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 +2  upvote downvote
submitted by โˆ—topgunber(68)
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thea hsti woehl mlreabcs tighn: nI one enli: 2 * q * 8%0.

hsTi is for eseisdda isulnavddii tow( q )lelae.slI = /60110 = Th 2^qe creyuqefn of q = 1/04

wNo cirraser si 2 p .q P is eocls to neo gnuimssa HW meq .1p=)+(q 'erehTs na ntdaidoail epts in tihs neitqsuo ude ot eth tow fefditern staumtnio.

so q(2) = ./102 80% of esteh rrcarsie are sodlneeti so iymtlplu 201/ * .08 = 51/2

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 +0  upvote downvote
submitted by thechillhill(1)
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p + q = 1 p2^ + qp2 + q2^ = 1 if q^2 = 1060/1 = 06.0030 e nth q = sqq2r)^(t = 2.005 lvse o rof p to etg p = 1 - r = 1 - .0502 = 5079. teh srgoteuhzeyo cerrrsia = 2pq = 1 - p2^ = 1 - 05.9 = .50 q2^ anc be pderdpo /cb s'ti mchu learmsl anth ^.p2 ehT edieonlt si plesnbriose for 08% fo teh oitnamu.ts 08. x 0.5 = 0.40 = 0140/ = /215

erheT mgthi eb an erseia awy ot od sith, btu it ekrwdo rfo .em

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thechillhill  So yplpatnrea I n'dot ownk how to famtor vyer wlel. ryoS!r +1
pakimd  oS abecues i ontudcl sepdn remo ahtn a etmniu no tshi eqoitnus adn holtseny ndtid clrela hte deniWbaergHyr- uteniqao htsi is owh i delosv it enrud a umotins e: ouy nkwo ni a gnevi iunopptaol half of tmhe wlli be rrircase senic sti na utmosaoal esviscree esasdei Aa =Aa AA aa Aa oAas fo taht ahlf 80% era due ot ndtleieo tustmnaio dna 2%0 ear eud iontp ymot tanubis hatt oglic 80% fo hafl otin 02% fo lfha llwi egvi yuo 251/ +1
draykid  .80 x 5.0 is 40. +
topgunber  heat tish ewolh smelrcab nhgti: In oen niel: 2 * q * i Th.s80% is orf esidades dliiindasvu o(tw q lla.Ilse)e = 1610/0 = ^ Thq2e euefncyrq of q = o4/wN01 rcrarise is 2 p .q P si seocl ot one usminags HW qme )p=+.(q1 hesr'eT an andliidtoa etps ni iths utoneisq due ot het wto eefdtfrni .tunomsoaits )2(q = .210/ 08% fo sehet ierracrs are lnoeeitsd os iutpymll 21/0 * 0.8 = 521/ +


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