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Retired NBME 20 Answers

nbme20/Block 3/Question#1 (reveal difficulty score)
The frequency of an autosomal recessive ...
1/25 ๐Ÿ” / ๐Ÿ“บ / ๐ŸŒณ / ๐Ÿ“–
tags: biostats

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 +16  upvote downvote
submitted by jotajota94(14)
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Ues eht nHWiearyr-gedb onqaueit

  1. aekT hte qseaur roto of /6001,1 dan ttah lwli igve ouy eht fyeeqrnuc of the ivesrcees aellle = 04/.1
  2. tlalceauC hte necqyurfe fo hte odmtnian ellael iwth =p+q,1 hchwi si =p .70.95
  3. ehyT are ngieltl uyo ot ealccltua het yecnrfeuq fo hte ssieeda resicra,r wihch is twih het ieuntoqa p2q.
  4. Thye twna nlyo the asdiees saecrrri ni hcihw detlione is rstpen.e To lclteuaca hi,st ues eth q evual 4/01() adn plutylmi yb %80 ni thsi dluhso evgi oyu .00.2
  5. ylFalin, cltaacelu rof P2 q2 0.7(()2)5=0.09 .400 = .2/51
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yex  !cNie .dan.. ew rae esoppuds ot edra teh semt dan do all tsih ni a nmeuti or os? /-: +28
charcot_bouchard  elellA nefeqryuc 0/41. os rriraec qerf /.201 %08 fo 102/ si 12/5 1(00/08 x 0)1/2 +15
dickass  hA kef,c p2q gto em +1
hello_planet  A nhyda csruohtt rfo rdynbig-eWearH is ahtt yuo glneelary anc maeuss p =~ 1 if q fi ayfrli .lwo It laos dtnes ot eb seaier ot okwr ni ianrftocs if the eanwsr ccsiheo aer ni ortifscan os oyu otnd' ahve ot eucbno ackb dan othfr betnewe rnsftciao nad m.ldiecsa So thiw ,ahtt oyu ndse pu hwit 2qp = 2 * 1 * 15/0 = /025 = 2/1.5 +9
topgunber  ahte sith helwo clasberm n:ghit I n eno ie:ln 2 * q * %h8i0. sT si orf dseesiad diidsnvuail (wot q saIl)el.el = 6/1010 = h2 T^eq fneeuqycr of q = w0/o 41N riarsrce is 2 p .q P is oslec to oen ussaimgn WH qme +(p.)q=1 eh'seTr na aliadtnodi tpes ni shti nutseioq edu to eth wot rnefitfde s.ntuaoomits )2q( = /210. 8%0 of ehest csrerari ear idoesetnl so iltylpum /012 * 0.8 = /512 +

@usmlecrasher

1/40 = .025 = q P + q = 1 -> P + .025 = 1 -> P= 0.975

+3/- alexp1101(11)

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 +2  upvote downvote
submitted by โˆ—topgunber(68)
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etah stih ewolh mlrebsac tnihg: n I neo i:lne 2 * q * 0%8.

sThi is for siddasee nudvidalsii ow(t q Il)elaels. = 600/11 = q^hTe2 unyfreceq fo q = 40/1

woN cesrrrai si 2 p .q P si eclso ot eon asigusmn WH qem =1)qp+(. T'eshre na taoiaidldn etps in htsi onstiequ eud ot eth two dftinerfe tunasi.tom

os )(2q = 1/02. %08 of sehte esrraicr rea tsndeeloi os tuilylpm 0/21 * 0.8 = 215/

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 +0  upvote downvote
submitted by thechillhill(1)
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p + q = 1 p2^ + 2qp + ^q2 = 1 i f 2^q = 1/6010 = .306000 e thn q = )qs2r(t^q = 50.20 os elv rof p ot teg p = 1 - r = 1 - 0.502 = .9057 the seyoehtozgur esarrirc = qp2 = 1 - 2^p = 1 - 90.5 = 50. 2 q^ anc eb pdoedpr /bc sit' uhcm srlelam naht ^2p. h eT dnleeoit is sseeibplorn for 0%8 of eth .untotiams 8. 0 x 05. = 0.40 = 0/104 = 5/12

hrTee imght eb an ieresa ayw ot od t,ihs utb it dekrow ofr me.

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thechillhill  oS ratenylppa I o'tdn nokw hwo ot rtfoam yrve wl.el yrSor! +1
pakimd  oS bseuaec i tondclu psned ermo naht a umtnie on tish ioqustne and ytslhneo itndd llcrae hte rHng-ediebyaWr tiuneqoa sthi is how i eodlsv it rendu a unmtoies: yuo wkno ni a igevn onuptpiaol hfla fo htem liwl be aicerrsr csein sit an otsaulamo secesiver eseasid Aa a=A AA aa Aa o Aas of hatt hlaf %08 era edu to elindote maitsutno nda %20 ear eud notpi tumyiato nbs ttha oiclg %80 fo half iont %02 fo lahf will egvi uyo 1/25 +1
draykid  .08 x 5.0 si 4.0 +
topgunber  htae iths lohwe smclbaer nhg:it nI oen l:nie 2 * q * 8ish% 0T. is rfo esddsaie idinvliuasd wto( q selI.el)al = 60/011 = 2^Thqe cefneyurq of q = 1o0/w 4N cerrrais is 2 p q. P is lsoce ot noe anissmug HW qme p1+.=q)( h'sreeT an aoitaidndl epst in htsi tnqsioue ude to the wot ertdeffin iostuamt.n so (q)2 = 12/.0 %08 fo eesth arercirs ear iotsnelde so itlpmuyl 21/0 * 08. = 2/15 +


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