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Retired NBME 20 Answers

nbme20/Block 3/Question#1 (reveal difficulty score)
The frequency of an autosomal recessive ...
1/25 ๐Ÿ” / ๐Ÿ“บ / ๐ŸŒณ / ๐Ÿ“–
tags: biostats

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 +16  upvote downvote
submitted by jotajota94(14)
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Ues eth y-HaginrdrbWee utaqeoni

  1. Teak het sqaeur toro fo 0/1610, dna atth will igev oyu het fneyqceur of eth reeisvsce ellela = .4/01
  2. tlaluCeac eth ufeeyncqr fo eth nmnadtoi elllea tiwh =pq+,1 hwchi si =p 9705..
  3. hTey ear lltenig uyo to eccllauat hte qcnfeyeru of the eesdasi cerrisr,a cwhhi is wtih hte qaetunio .q2p
  4. hTye awtn lyon teh esdiaes rcsareri ni cihwh entdolei si t.epnsre oT caetulcla ih,st eus teh q uvlae )401(/ adn pymtulli by 0%8 in iths oshdul evgi uoy .02.0
  5. lFia,lyn luacletca for 2 Pq2 090.52()70).(= .040 = .152/
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yex  ic!Ne .d..an ew rae seduppos ot daer teh smte dan do lla siht in a umietn ro ?os :/- +28
charcot_bouchard  elellA fnycrqeeu /401. so rrcaeri fqre .102/ 08% fo 1/02 si 21/5 0/81(00 x 12)0/ +15
dickass  hA ek,cf 2qp tog em +1
hello_planet  A ynhda tutrcsoh rof eageWrH-niybdr is atht oyu aneglrlye nac asumse p =~ 1 fi q if fialyr wl.o It oasl dtsne to eb sierea to wokr ni sacrifnot fi eht wseran hosecci rae ni nfcsortia os uyo od'nt veha ot ecubno acbk and tfhro eetbenw siftnacor dan isealc.dm o S twhi h,att uyo neds pu ithw 2pq = 2 * 1 * /150 = 205/ = 21/.5 +9
topgunber  ehat hits lehow beasrmlc :tihng In eno :lien 2 * q * hTi%08.s is fro easeddsi vlusdadiiin (otw q l.leIaesl) = /10160 = T ^h2eq neycfrque of q = oN1/40w sarirecr is 2 p .q P is slceo to eon isuansgm WH emq +=q.)(1p ehTrse' an ddltianiao epst in isht tqiusnoe due to eth wot rifndetfe tstsi o.aomun )2q( = .2/01 %80 fo sheet iscrerar aer tlsdeoein os tilpumly 0/21 * 08. = 5/21 +

@usmlecrasher

1/40 = .025 = q P + q = 1 -> P + .025 = 1 -> P= 0.975

+3/- alexp1101(11)

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 +2  upvote downvote
submitted by โˆ—topgunber(68)
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aeth sith hwoel blamcers :hgitn In eno einl: 2 * q * %08.

siTh si rof dsdaseei lnusividida wt(o q alI.leels) = 1100/6 = T2^qhe euyefqcrn of q = 4/01

wNo raresicr is 2 p .q P si olcse to eon giusnams WH eqm p(=)+q1. herseT' na adlontiiad epst in stih qiensout ude ot het wot tefdiefrn nta.sumoit

so ()q2 = 20/.1 80% fo sheet rsraeric rae tieoelnds os itlupmly /012 * .80 = 152/

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 +0  upvote downvote
submitted by thechillhill(1)
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p + q = 1 2p^ + pq2 + ^2q = 1 i f 2^q = 010/16 = 00.3006 neth q = 2t(^sqr)q = 2050. vleos for p to get p = 1 - r = 1 - 2.050 = 79.50 eth oegzyuhsroet eacirrsr = 2pq = 1 - p^2 = 1 - 09.5 = 5.0 ^2q cna be pedodrp /cb 'sit mcuh asmlelr tnah ^.2p eh T elideont is eoinersblps orf 0%8 fo eth mnats.itou . 08 x 5.0 = 04.0 = 401/0 = 2/15

Teher mthgi be na ieaesr ayw ot od th,si utb it wrokde rof .me

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thechillhill  So ynetparalp I o'tdn konw who ot rofmat vyre el.wl roS!yr +1
pakimd  oS seaecub i cudtnlo dpnes mero tnha a muiten no ihts itounqse adn yelohnts ddnti elrcal hte nydgar-eireHbW toeuaniq tshi si how i vdeslo ti uednr a :tmi sonue oyu kwno ni a ginev ltonpoipau lahf fo meth iwll be sreiarrc sinec sti na tauoalsom erevssiec isaeesd aA Aa= AA aa aA aAos fo ahtt ahlf 0%8 aer due to eeildnto tuotmiasn dna 2%0 era due tnoip tn ostabmuyi ttah gcoli 80% fo lhaf otni %20 of falh lwli egiv uyo 1/25 +1
draykid  08. x 50. is .40 +
topgunber  heat shit elowh elcabrsm hitng: I n eon n:eli 2 * q * 0sh8%Ti. is ofr ddasesie dlsauinviid o(tw q aell)Is.le = 1610/0 = q2T e^h eeqfncryu fo q = ow4N0/1 rrascrei si 2 p .q P is esclo to one gusansim WH mqe .q+(1=p) hreTs'e an ndiatdioal setp ni tsih itunoesq edu to hte owt fidertnef oui.ont mssta q2)( = 1/2.0 %80 fo heste riarercs rea deltinsoe so mtpliyul 201/ * 0.8 = /215 +


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