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Retired NBME 20 Answers

nbme20/Block 3/Question#1 (reveal difficulty score)
The frequency of an autosomal recessive ...
1/25 ๐Ÿ” / ๐Ÿ“บ / ๐ŸŒณ / ๐Ÿ“–
tags: biostats

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 +16  upvote downvote
submitted by jotajota94(14)
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sUe eth WrbrineH-yadeg untiaqoe

  1. kTae the urqase toor of 11006/, nad thta lwil evig uyo the ycfuqenre fo het ireevcses eaelll = /40.1
  2. auclaCetl eth neceuyrfq fo hte iotnanmd ealell iwht q,p+=1 hwihc is p= 05..97
  3. yThe ear tenilgl ouy ot uaclclaet teh eunyeqcfr of the edseasi iarrercs, wchih si whit the ionqatue .p2q
  4. eThy want nylo eth eaesdsi resirrac in ciwhh ideolten is ren.estp To ccallteua h,tis eus eht q aeuvl 04)1(/ adn pltiumyl by 0%8 ni thsi uoldhs evgi uyo 2.0.0
  5. Fa,nilyl aaleuctcl ofr 2P2q 0)702=0(.(9).5 .400 = .51/2
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yex  !iNce d.na.. we are ppdssuoe ot ared the estm nad od all tshi ni a mtinue ro so? /-: +28
charcot_bouchard  elllAe nfecqyeru 40./1 os rierrca frqe .2/01 %80 of 1/20 is 215/ 080/0(1 x 10)2/ +15
dickass  Ah c,kfe q2p ogt em +1
hello_planet  A dhnya sutohtrc rof -HdibyrgaenWre is that you eenlralgy acn eusasm p =~ 1 fi q if ryafil .lwo tI losa stnde to eb eesria ot work in ifacnostr if eth ewrnsa eiohccs rae ni ctiofrnas so uoy not'd hvae to enuobc kbca adn ofrth weenetb rtanofsci nad sa.ilcdem S o thwi taht, yuo dens up htwi p2q = 2 * 1 * 1/05 = 0/25 = .15/2 +9
topgunber  teha sthi lwhoe secrmlba gihn:t n I one :ieln 2 * q * hTi.% s80 si rof edissdae niidsuaivdl (wto q se)ll.Iale = 01016/ = qeh2^ T fuycrneqe fo q = N10o/4w sreracri si 2 p .q P is clsoe to one usmnsgai WH meq 1=(q)p.+ sTree'h an ddloiitaan pets ni tsih qnostiue deu ot teh two ftdrifnee m ostu.naiost )2q( = /12.0 8%0 of etehs ricsrrae ear dlenistoe so pyiutlml 21/0 * .80 = /125 +

@usmlecrasher

1/40 = .025 = q P + q = 1 -> P + .025 = 1 -> P= 0.975

+3/- alexp1101(11)

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 +2  upvote downvote
submitted by โˆ—topgunber(68)
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heta hsit hweol lrmbcsea ht:gin nI eon e:inl 2 * q * 80%.

iTsh is rfo ddesaies vandilisuid (wto q .s)ealllIe = 611/00 = T hq2^e uercnfeqy fo q = 0/41

owN crersair is 2 p .q P si elcos ot oen sniuamgs WH qem p)(q=+1. Thees'r na indaoitlad ptse in thsi unqiseto edu to eth two fftdeienr tnao.sitmu

os q)(2 = 02/1. 8%0 of eesth crraiers era nsloetied os mtpuylil /021 * 08. = 21/5

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 +0  upvote downvote
submitted by thechillhill(1)
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p + q = 1 2^p + pq2 + 2q^ = 1 f i q2^ = 00161/ = 060003. hen t q = rt2^qsq)( = .5002 vl ose orf p to egt p = 1 - r = 1 - 0502. = 590.7 th e uzeryogeosht scerarri = 2pq = 1 - ^p2 = 1 - 5.90 = 50. q 2^ anc be odpepdr c/b t'si umhc samellr nhat 2.p^ heT tnedileo si eonslersipb orf 0%8 of het oaits.umnt 08. x .05 = 004. = 0/410 = 251/

erheT hgmit eb an seaeir ywa ot do tih,s utb it drwkeo for .me

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thechillhill  So taeplranyp I d'nto wnko woh to fmoart rvye ell.w ryr!oS +1
pakimd  So ecuasbe i clnduot npesd roem ahnt a unitem no thsi esntouqi dna nlosehty ddnit rcalle hte iered-WnabgrHy unaetqio sith is owh i lovdes it ndeur a esm:iun ot uoy kwno ni a inveg uaptpoloni ahlf fo tmeh liwl eb ircsrera iensc its an tmoloaaus vreiessec esdeasi Aa =aA AA aa Aa aAos of that afhl %08 rea ued to ileoendt uittanoms nda %20 rea due tonpi at umotnybis atth golic 08% of hfla itno %02 of lhaf liwl iveg oyu /125 +1
draykid  08. x .05 si 4.0 +
topgunber  ahet hsit hweol srbeclam gnt:hi nI eon en:il 2 * q * hi.0T%8s si rof sdiaeeds niadlsudiiv tow( q lle)lsIae. = /11600 = ^2eq hT frneycueq of q = 4o/ 10wN rarisrec si 2 p .q P si esloc ot oen igsumnsa WH emq p=+q)1.( Thsr'ee an iiltdonada ptse in sthi eiunsotq ued to teh tow defirfnet o.ostts auinm )2(q = ./120 0%8 of heets rcsreira rae iedlntoes os lyupilmt /021 * .80 = 521/ +


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