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Retired NBME 20 Answers

nbme20/Block 3/Question#1 (reveal difficulty score)
The frequency of an autosomal recessive ...
1/25 ๐Ÿ” / ๐Ÿ“บ / ๐ŸŒณ / ๐Ÿ“–
tags: biostats

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 +16  upvote downvote
submitted by jotajota94(14)
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eUs eht idgyr-ernHWeab aeoqutni

  1. Tkea hte suqear ootr fo 11060,/ nda atth wlil gvei yuo teh crqfneyeu of hte riscsevee lelela = /0.14
  2. aCtlaeucl the ryqcuneef fo hte aimdnotn leaell wthi =+q1,p wcihh si p= .5.097
  3. eThy era lliengt oyu ot lalaccteu teh unreeyqfc fo eht deisaes asecr,rri whhic si htiw hte qinetoau q2p.
  4. eTyh awtn lony eth seiadse sirercra in cwihh ltnideoe si s.nrpete To aclueltca t,his eus the q aluev 10/)(4 dna mlplyiut by %80 ni isht hsoldu gvei you .002.
  5. Fyalnil, aluelccta orf 22Pq (=700..2(90))5 0.40 = 521/.
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yex  iecN! ...and we ear udoespsp ot rdae eth emts dna do lal tihs in a mtinue or so? /:- +28
charcot_bouchard  lelAel feqcyuner 014./ os irrrace refq 0.21/ 80% of /210 is 1/25 01/8(00 x 201)/ +15
dickass  hA e,kfc 2pq otg em +1
hello_planet  A nahyd thsrcout ofr be-dHyWinargre si htat oyu llrengaye nac asseum p ~= 1 if q fi yafilr wlo. It sloa nsted to be seaire ot wrko ni ifostnrac if het swaern ihcsceo era ni fnotrscai so you 'otnd vhea ot ecounb kacb dna thrfo tenweeb rocafisnt nad a.lmisdec So ihwt tat,h oyu snde up hiwt 2pq = 2 * 1 * 510/ = 052/ = 1.2/5 +9
topgunber  aeth ihst lwheo sacrlbem nhgti: nI neo ile:n 2 * q * T%hi8s.0 is ofr dadsseie undivlisaid two( q e)s.eaIlll = /11600 = e qhT^2 yefucqrne fo q = Nw 4o10/ rceirars si 2 p .q P si clsoe to eno uginamss HW qme (q1+=p.) eTsr'he an tialdoiand tpse ni thsi soqntuei edu ot eth two dfreintef no.sauotmtsi )2(q = 2/0.1 8%0 fo heset rarisecr aer osendliet so lmiytpul 21/0 * 0.8 = /215 +

@usmlecrasher

1/40 = .025 = q P + q = 1 -> P + .025 = 1 -> P= 0.975

+3/- alexp1101(11)

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 +2  upvote downvote
submitted by โˆ—topgunber(68)
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heat tish lweho lesmcbar ihtng: n I noe ni:le 2 * q * 8%0.

Tshi is fro dsseaedi iulandiidsv w(to q lslIae)le. = 16001/ = ^ eh2Tq eqfreyucn fo q = /014

oNw rrircsae si 2 p .q P si csloe to one samisngu HW meq .p(=)1+q sT'rhee an tanoldiiad tspe ni stih einqsuot eud to hte tow tffnieerd .tmiusonat

so (q)2 = ./210 8%0 fo htese rcerirsa are ensiltdoe so imlluytp 12/0 * .80 = /251

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 +0  upvote downvote
submitted by thechillhill(1)
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p + q = 1 2^p + p2q + q^2 = 1 if ^2q = 160/01 = 603000. hte n q = t(qs)q2r^ = 2005. lvsoe for p ot get p = 1 - r = 1 - 0502. = 9.075 het guyrohsezteo errirasc = 2pq = 1 - ^p2 = 1 - 059. = 50. 2q ^ cna eb pdrepdo /cb t'si cmuh rlasmel naht p.2^ Teh ldneiteo is lsieboenprs orf 0%8 of het ona.tumist 8 0. x 50. = .040 = /0104 = 152/

eTrhe hmigt be na eresia yaw to do t,ihs but it edkrwo rfo .em

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thechillhill  So aratlpeynp I 'ndto okwn who ot artmof ryev .ellw orSr!y +1
pakimd  oS cabuese i lodtcnu sdnep eomr tanh a ntimue on hsti eonutqis dan eltohsyn tiddn lelacr the -erWadbgeHiryn ouaqietn this si how i vloeds ti enurd a imn ots:eu you wkno in a igvne oaupoiltnp hafl fo etmh ilwl eb eirrcasr insec sti na atouosalm escirevse siseead Aa Aa= AA aa Aa so Aa fo ttha lahf 08% are ude ot tneeloid tmnitasou nad %02 rae due npiot amy uonbstit atth ligco 80% fo hafl ntoi 2%0 of lfha lilw evgi uyo 52/1 +1
draykid  .80 x 05. si 0.4 +
topgunber  htea htis olhwe carbmsle iht:ng In noe il:ne 2 * q * Ts8h%i0. si rof esaidsed anlsudiidvi wt(o q s).elaIell = 0611/0 = eq^hT2 yncfruqee fo q = 1 N/4w0o iscrearr is 2 p q. P is ceols ot one asgsuinm HW mqe .q)1=p+( esrheT' na tiidlnoaad tsep in tihs tnouqeis edu to eth wto nitfdefre msoutt osnia. (2)q = 21/.0 %80 fo these ircserar are iletsdneo os mypltliu 0/21 * .80 = /521 +


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