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Retired NBME 20 Answers

nbme20/Block 3/Question#1 (reveal difficulty score)
The frequency of an autosomal recessive ...
1/25 ๐Ÿ” / ๐Ÿ“บ / ๐ŸŒณ / ๐Ÿ“–
tags: biostats

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 +16  upvote downvote
submitted by jotajota94(14)
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seU hte anri-HbdWyegre nqaoieut

  1. Teka the uaqrse otor of 160,/10 dna atht lilw gvei uoy het fyueencrq of teh erveesics elaell = /41.0
  2. lcalaeutC eht qnrfceeuy fo hte tdnmnoia lelael whti 1+,q=p wcihh is =p 790.5.
  3. eyTh era lligetn ouy ot cetaalucl het neryceqfu fo hte esiadse acirrres, whhci is tihw hte noeaiqtu pq2.
  4. yehT wtan loyn the eesadis sirrarec in ihcwh tledinoe is pnere.st oT cualcelta st,ih eus hte q uvlea 0)4/1( nad liyuptml yb 08% in hits uodhsl eivg oyu .20.0
  5. l,ianFyl caactleul rfo 2q2P =529(0)70(..0) 40.0 = /.215
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yex  ieNc! .nda.. ew rea deupposs ot dear het mset nad od lla shti in a iutmen or ?os /:- +28
charcot_bouchard  lleAle qyefercnu /0.41 os irercar qfer 2.0/1 80% fo 2/01 is 1/25 00/1(80 x )01/2 +15
dickass  hA eck,f 2pq got me +1
hello_planet  A hnayd rtuctohs rfo HWrbygi-eeardn is htta uoy yellgraen can aumess p =~ 1 fi q if ifyral wo.l tI aols sntde ot eb srieea ot rowk in iafstcnor if eht nwares isohecc ear in cstoiarfn os uoy nd'ot evah to cenbou bkca nad othrf tnebwee cfrtnoias and clsa.emid oS thwi ha,tt oyu dnes up wiht 2qp = 2 * 1 * 51/0 = 50/2 = 215./ +9
topgunber  hate sthi whole earlsmcb gh:int nI noe line: 2 * q * Th 0%8si. is rof eiddseas uidisvadnil (wto q lesle.Il)a = 1/0061 = 2The^q yeenufcrq fo q = N 1/4ow0 isrecrar is 2 p q. P si seolc ot eon ausmigsn HW qem =(.q+)1p eThs're na aaitidonld espt ni tsih utoseiqn due to hte two ifentfedr issan too.tmu )2q( = 01./2 0%8 fo htese riaescrr era ledseotni so imlyltup 1/02 * 80. = 21/5 +

@usmlecrasher

1/40 = .025 = q P + q = 1 -> P + .025 = 1 -> P= 0.975

+3/- alexp1101(11)

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 +2  upvote downvote
submitted by โˆ—topgunber(68)
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tahe isht elwho lmbsaerc ni:hgt nI neo ine:l 2 * q * 08%.

ihsT is for adeesdis diualdvsini tow( q alsIl).ele = 160/10 = T2^e hq eqerucynf of q = 04/1

oNw rriaercs is 2 p q. P si oslce ot noe amnissgu WH meq 1+q=p.)( rsTee'h an ilnodidata tsep ni stih qsitoenu ued to hte otw fdtefeinr a.tsinoutm

os 2q() = /10.2 0%8 fo heset easrcrir rae ideetnlos os uitlyplm /210 * .08 = /251

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 +0  upvote downvote
submitted by thechillhill(1)
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p + q = 1 ^2 p + 2qp + 2^q = 1 i f 2q^ = 10/106 = 300.600 hetn q = 2(tsrq^)q = .2500 vesol ofr p ot gte p = 1 - r = 1 - 200.5 = 095.7 he t yheztosreoug cseriarr = qp2 = 1 - 2p^ = 1 - .950 = 0.5 q^2 nac be podeprd cb/ it's mhuc lelsmra ahnt 2^.p The toenlide si ioensrlpesb rfo %08 of het umi.oatnts 8.0 x 50. = 040. = 1/004 = 21/5

eTreh imhtg eb an searie awy to od shit, btu it ekwdro rof .em

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thechillhill  So aapertpnyl I 'otdn nokw owh to mortfa ryev lwl.e rr!Soy +1
pakimd  So abeusec i dnutocl spdne oerm nath a itnmue on htis oqnesitu dna nloysthe intdd allcer hte -nebygdHWeairr eitnqoau ihts si ohw i evosld ti nerud a :snem iotu uoy wkno in a gveni tpilpanouo hlaf fo hemt llwi eb ciaesrrr ecins tsi an ouasamolt eersvecsi eidseas aA A=a AA aa Aa Aa so fo htat flha %08 rae due to neoldeit itamtnuso dna %02 rae eud piotn iysbttoamn u thta lcoig %08 fo half onti 02% of hafl llwi vige ouy 15/2 +1
draykid  8.0 x 5.0 is 0.4 +
topgunber  haet htis eholw arcsmble ting:h In one lei:n 2 * q * %ihs8T0. si rfo eseadsdi duislaivdin ot(w q slll.eaIe) = 0161/0 = hTq2e^ eryqnfuce fo q = Nw o14/0 airrcres si 2 p .q P is sleoc ot neo nusmgisa WH eqm +q)(1p=. Tseh'er an tnaoiddlia pset in sith qoutnsei ude ot teh wot rdienffet tosunmoisa. t )q2( = .02/1 08% fo teseh rsiarrce rea ensidlteo os tpumylil 1/20 * .08 = 251/ +


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