NBME 20 1/25 (NBME Answers)

Retired NBME 20 Answers

nbme20/Block 3/Question#1 (reveal difficulty score)
The frequency of an autosomal recessive ...
1/25 🔍 / 📺 / 🌳 / 📖
tags: biostats

+16 upvote downvote
submitted by jotajota94(14)

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eUs het rHWrndi-aebgye eiutqnoa

keTa eth usarqe orot fo 10160,/ nda ttah lwil ivge ouy teh enryefuqc fo teh ssveereic ealell = 1/04.
uaCclelta the fqnurceey fo teh ndimtnao aleell ithw =qp1,+ ihwch is =p 750..9
ehTy ear llgeint uoy ot ltacceaul teh ureeqyfnc of eht idsaees rsrae,rci whhic is twhi hte qetauoin q.2p
Teyh tanw nylo teh aesesdi eiarrrsc in hcihw oeendlit is enpetsr. To catuelcla i,sth esu teh q leauv 1()04/ nad mluptliy yb 08% ni shit lusdoh give you 20.0.
nFiayl,l accltelau orf q2 P2 009=.02).5()(7 40.0 = .5/21

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yex c!Nie .nad.. ew rae sodespup ot drae het stme dan do lla ihts in a netumi or ?so -/: +28

charcot_bouchard llAlee eruyqfcen /01.4 os rrceira eqfr 1./20 08% fo /012 is 15/2 180/0(0 x 02/1) +15

dickass Ah kfce, pq2 ogt me +1

hello_planet A hadyn sohurttc rfo -nyHgbWarrdeie is hatt uoy ernygalel acn esmusa p ~= 1 fi q if fairyl .wlo tI alos desnt to eb eeirsa ot orkw ni oisrncatf fi hte wnrsae ichesco ear in ctrainfso so uoy n'dto veah to cnbueo bcka nad thofr eebwtne onaticsrf dan esdcla.mi S o with atth, ouy edns pu wthi qp2 = 2 * 1 * 10/5 = /025 = /.521 +9

topgunber ehat tihs elowh maerbscl :nhtgi nI oen :leni 2 * q * hi08%T .s is ofr sesaiedd liviudandis wot( q )Ileael.ls = /60101 = hTe^2q ceequnfyr of q = /N4o 0w1 arrcseri si 2 p q. P si lcose to neo nuagmiss WH emq ).(p=q+1 hT'erse an nlioatddai spte ni tshi oiusqten due to het wto dfereitfn n stamtisuo.o 2(q) = 2/.01 08% of hetes airscerr era tndeelosi so lmpiluty 0/12 * .08 = 152/ +

@usmlecrasher

1/40 = .025 = q P + q = 1 -> P + .025 = 1 -> P= 0.975

+3/- alexp1101(11)

+2 upvote downvote
submitted by ∗topgunber(67)

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teha stih whoel cmerabls n:itgh In one ein:l 2 * q * 8%0.

ihsT is rfo eiedssda nsiuidldiva two( q ls.l)leaIe = 1601/0 = qe^hT2 fyceeruqn of q = 4/01

oNw rcireasr si 2 p .q P si elosc ot oen gusiamsn HW emq q.=)1+p( seThe'r na adoianlitd tsep ni ihts iesunqot edu to eht wot tirfenedf suttni.mao

os )q(2 = 02/1. %08 of hsete iscrarer rae otieelnds os utmiplyl 021/ * .80 = /512

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+0 upvote downvote
submitted by thechillhill(1)

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p + q = 1 2^ p + 2qp + q2^ = 1 i f ^2q = 16/001 = 60003.0 ten h q = qs(tr)2^q = 50.02 elsov rfo p ot get p = 1 - r = 1 - 2005. = 59.07 e ht yorohuezsget asercirr = qp2 = 1 - 2p^ = 1 - 509. = 50. q^ 2 nca eb dpdorep /bc 'sti uchm mlrslea than p.^2 T eh iloenetd is esrpbonesil orf 08% of the ouiasn.mtt 0. 8 x 50. = 40.0 = 1/040 = 1/25

eehTr gthim eb an areeis way ot od ,ihts utb it rkoewd for .me

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thechillhill So pnataelypr I not'd nwko hwo to ofamtr ervy .llwe rSry!o +1

pakimd oS esbecau i lcundto esnpd rmoe hant a imutne no ihts ounisqte adn ytohesnl itndd laelcr eht rdgbeyainr-HeW quaineot itsh is hwo i olesdv it rendu a nmes:otiu ouy okwn ni a ivnge panoouptil lfha of hmet will be srrcarie ciesn its na osoumaalt sersiceve dasiese aA =Aa AA aa aA as oA fo taht afhl 8%0 rea ude ot idleoten itstuomna nad %02 aer deu potin it tuyonamsb taht lcgoi 0%8 of hlaf inot 02% fo hfal illw eigv yuo 2/15 +1

draykid .08 x 05. si 4.0 +

topgunber etah thsi holwe emlsabrc :htnig nI neo :neil 2 * q * 0%i8hTs. is for edissaed adsiuinlvdi t(ow q ell.)eIlsa = /01016 = q2 h^Te nrcequyfe fo q = N 1w/o04 ircrrsea is 2 p q. P is slcoe to eon ingsusma HW qme (.+)q=p1 hre'seT na oaddiitanl sept ni ihts nseiqtou ued ot eth wto nfefertdi mao.utns tiso )(q2 = 20.1/ 0%8 fo these rcrearsi rea eiestodnl so imtyllup 10/2 * 80. = /512 +

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