NBME 20 1/25 (NBME Answers)

Retired NBME 20 Answers

nbme20/Block 3/Question#1 (reveal difficulty score)
The frequency of an autosomal recessive ...
1/25 🔍 / 📺 / 🌳 / 📖
tags: biostats

+16 upvote downvote
submitted by jotajota94(14)

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Ues het rHdgnre-yWabie onuetiqa

Teka eht rsaeuq toor fo /00116, dan that lwli eivg you het ycrneuefq fo the irseeevcs lleeal = 1/.04
Calelctau the cerqneufy fo eht dinmntoa eallle ihwt =1q+,p cihhw si p= 075..9
ehTy rae nlitgel oyu ot lucetcaal eht rcyuefqen of eth seesiad srer,rcia hwhic is twhi eht oiqnutae pq.2
yeTh awnt yoln teh dseisea rrsiecra ni wchhi tieondel is ntp.sere oT lcateaucl th,is use eth q aulve 10()4/ dan umpltlyi yb 8%0 ni isth ohulds gvei oyu ..002
,llniyaF ultccleaa for 2 2Pq 0(=0).2079).5( 400. = 51/2.

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yex icN!e ..da.n ew rea seupspdo ot read hte stme dan do lla sthi ni a nitemu or so? :/- +28

charcot_bouchard eAlell efenrcqyu /4.10 so riacrer rqef 12.0/ 08% of 012/ is 21/5 /(00081 x 1)0/2 +15

dickass hA k,efc qp2 ogt me +1

hello_planet A hdayn scuhtort orf debWe-ygrarHni is htat oyu aylnlgeer nac saumse p =~ 1 if q fi ryilaf wol. It lsoa sdten to eb raesie to owrk in tnfsrocai fi the saerwn scioceh era in sntfiorac os oyu d'ton ehav to euocnb kcab dan fhtor btneeew nfactsoir adn lsm.eicda o S whti ,taht you sden up htwi qp2 = 2 * 1 * 51/0 = 5/20 = 5/.21 +9

topgunber haet ihts loweh mcabserl tnig:h In eon e:nil 2 * q * T s.%0hi8 si rfo adedsise dasunviildi ot(w q )lslleaI.e = 10016/ = h^ Te2q feucqryen fo q = 04woN /1 rrsraiec is 2 p q. P is lesco ot one anumsgsi WH emq .+p=q)(1 rseThe' an adadltonii tpes in sthi iteqosnu ude ot the wot fdriteefn u smost.itnao )2(q = /012. %80 of heest eicarsrr aer tesondeil so umiltlpy /120 * 08. = 12/5 +

@usmlecrasher

1/40 = .025 = q P + q = 1 -> P + .025 = 1 -> P= 0.975

+3/- alexp1101(11)

+2 upvote downvote
submitted by ∗topgunber(68)

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heta ihts ohelw elrcsbma ghnt:i nI neo iln:e 2 * q * 08%.

shiT is for sdesaeid siadvdiunil (otw q .eelllIa)s = 010/16 = Tqe2^h fcnyqeeur fo q = /041

wNo seraircr si 2 p .q P is oelsc to eno ssnumgai WH qme .=()+qp1 resh'eT an daitnlioad ptse ni stih tnisqoeu ude to eth tow deefirtnf ntmusa.ito

os (2)q = 2./01 80% of ehtse irscrare era ltnieedso os luymtlip 210/ * 0.8 = 2/15

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+0 upvote downvote
submitted by thechillhill(1)

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p + q = 1 ^2p + p2q + ^2q = 1 fi ^q2 = 61001/ = .000306 hnet q = qrqs2)^t( = 005.2 vo els fro p ot gte p = 1 - r = 1 - 2005. = .7950 het ohrgoeutsezy rscraeri = pq2 = 1 - p2^ = 1 - 059. = 50. q 2^ nac eb edrppdo /bc t'is uchm lsrelam athn ^.2p hTe edoinlte is epersobnisl rfo 08% of eth nut.isatmo 0 8. x 5.0 = 0.04 = 0014/ = /512

eheTr tgmih eb an raseie way ot od ,ihts btu ti wrodek orf .me

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thechillhill So eyapanptrl I od'tn wnko ohw to arftmo very .ellw rrS!oy +1

pakimd oS ceubesa i undltco desnp rmeo naht a uetimn on iths eoisqtun and ehytsnlo dtnid acrell teh e-deynbirHgraW auitenqo ihts is hwo i deslov ti dreun a s: ntmueoi uoy nokw ni a eving ouonaptilp falh of htme lliw eb irrasrce eicsn sit na lsuaatoom eivsrscee sieadse Aa Aa= AA aa aA soAa of atth hfla %08 ear ued to lnotdeie mouitnast nad %20 rae ude niopt obnautmsity ttha gcoil 80% fo fahl oitn %02 fo afhl will veig uoy /512 +1

draykid .80 x 5.0 si 40. +

topgunber tahe sthi hlowe acsermlb ihn:tg nI one nle:i 2 * q * 8.0Th %is si ofr aiddeses dviilanudis (two q esl.a)Iell = /60110 = heT2^q unycqreef of q = 1o0N w/4 sierrrca si 2 p q. P si coels ot one amisngsu HW meq p)=+1q(. rh'eTes an ldtadnoaii tesp in tsih uitenqso ude ot teh tow fefirnetd i.attu osmson )(q2 = /210. 8%0 fo ethes aercrrsi are ntedlseoi os tyuipllm 2/01 * 8.0 = /215 +

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