sUe hte ynriabdHeWgr-e uetnaiqo

1. aTke eht aqrues root fo 0,/6011 nad that lliw gvei uoy eht eyufqcnre of teh crvsesiee eellla = 0./14
2. taecualCl eth yeeqnrcfu of hte tdmnoani allele tihw q+1=,p ihchw si p= .0.795
3. yhTe era leintlg oyu to utlaaccle teh neqercufy of eth saidsee ,rcaierrs chwih si tihw eht noeuaqit 2.pq
4. eThy twna noly eht aiedess reraircs ni ihwhc itndeloe is .sernpte To elalacuct htsi, seu eht q eavlu 14()/0 and lmypitlu by 08% ni hsti lohusd veig oyu .02.0
5. n,Fliayl ltaulacec rfo 22Pq .5.20)90(7)0(= 40.0 = 25/.1

heta tihs whoel eclramsb hitng: In neo e:lni 2 * q * 80%.

hTsi si rfo asseiedd dunlidsiiav ow(t q aeIlsle)l. = 61100/ = 2hqT ^e eneuqcryf of q = /401

oNw eriacrrs si 2 p .q P is cselo to one gsnumisa WH mqe )+(1q=p. seheT'r na ddoaitianl teps ni isht etisuoqn eud ot teh owt ndefiftre uta.mtsino

os )2q( = .102/ %08 of ethse rrcrisae rea etdoeslni os lmtpluiy /210 * 0.8 = 1/52

p + q = 1 p^ 2 + 2qp + ^2q = 1 i f q^2 = /01610 = .000603 hte n q = s(2tq)r^q = 5002. esolv for p ot teg p = 1 - r = 1 - 00.52 = .5097 het gthyeurzooes ircraser = q2p = 1 - 2^p = 1 - 50.9 = 5.0 ^q2 acn eb dorppde /cb t'si mhuc rmalels athn .p^2 e hT netlodei si posnslribee for 80% of eht isout.tanm .08 x .50 = .040 = 001/4 = 52/1

Teehr thgim eb an irease way ot od sht,i but it rdowke for m.e