NBME 20 1/25 (NBME Answers)

NBME 20 Answers

nbme20/Block 3/Question#1 (reveal difficulty score)
The frequency of an autosomal recessive ...
1/25 🔍 / 📺 / 🌳 / 📖
tags: biostats

+16 upvote downvote
submitted by jotajota94(14)

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eUs teh eWbgrnr-eyidHa enutaqoi

aekT the aquser orot fo 1,1/006 dan htat wlli egiv oyu eth uerfcqyen fo het cseierves allele = 41.0/
aueatcllC hte enqcuyfre fo teh idntmaon elalle hwti q+1=p, hicwh is =p 05..79
Teyh aer telnlgi uyo to laucltace hte efyqenrcu of teh esesiad sirae,crr chwih is ihwt het itanqueo p2.q
ehyT awtn ylon eht eisdeas seracirr in icwhh oitelden si etrse.pn To lculteaca s,hti ues het q uavel 4/(0)1 dna lilptymu by 80% in ihst lhdsuo igev you 0.0.2
liFla,yn lcltceaau fro Pq22 502.=.))(0790( 04.0 = 1./52

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yex ieN!c ..n.ad we rea pepdssuo to drae teh smet dna od all itsh in a neiumt or os? -/: +28

charcot_bouchard ellleA ueeqfcyrn .4/01 os rcrreai erqf 01.2/ %80 of 12/0 is /251 800(/10 x 2/)10 +15

dickass Ah ef,ck qp2 got em +1

hello_planet A ydnah huortstc for anWe-ygdrbHier si ttah oyu learegyln cna uamess p =~ 1 fi q if afryli w.ol tI loas dsent to eb asriee to kwor in otfanircs fi the swaern choceis aer ni nrfsotcia os you dtno' veah to ocuebn abkc nad thfor weeebtn tnifcasro dan csm.iedla oS hitw tha,t ouy dnse pu twhi 2qp = 2 * 1 * /015 = 5/02 = ./521 +9

topgunber heta shti ehwol lsmecabr tngi:h I n one i:nle 2 * q * %h8T is0. is fro issaeded dialisindvu wot( q s.leal)elI = 01016/ = 2qhTe^ nycqrfeue of q = w 041/oN rscirrae is 2 p q. P is lsceo ot noe gsmiusna HW emq 1.=pq(+) Tr'eehs na lanoidtiad epst in hsit qiuosnte eud ot teh otw drtnfeief nutias tos.mo 2q() = /2.10 8%0 of seeht esarcirr are soelndtei so mpllyiut 12/0 * 0.8 = 215/ +

@usmlecrasher

1/40 = .025 = q P + q = 1 -> P + .025 = 1 -> P= 0.975

+3/- alexp1101(11)

+2 upvote downvote
submitted by ∗topgunber(67)

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htae isht wehlo ecbrsalm :htign nI oen ie:nl 2 * q * %08.

sihT si rof eeadisds sdaiuvndlii two( q )a.lleeIls = 60110/ = qh 2eT^ ferucneqy fo q = 0/41

woN esarrcir is 2 p q. P is slceo ot neo usigamsn HW mqe .=+)1qp( hs'Tere an oldntiaaid spet in isth teoqusni ued ot eht otw feferitdn mstoinatu.

so q2() = 1.2/0 08% fo ehset rriearcs ear osieletdn so mlpltiuy /021 * .80 = /152

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+0 upvote downvote
submitted by thechillhill(1)

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p + q = 1 2p^ + q2p + ^2q = 1 fi q^2 = 0/1601 = 603000. ehnt q = ^qtrq)(2s = 2.500 e solv rfo p ot tge p = 1 - r = 1 - .2500 = 597.0 eth retyhzogoseu srcreiar = 2qp = 1 - ^2p = 1 - 9.50 = 0.5 q^2 nac be prpddoe c/b sti' cumh relsalm hatn ^2p. e hT nieedlto si pbelssreoin rfo %80 fo het oastmti.un 8 0. x 05. = 4.00 = 014/0 = 1/25

Theer tihmg be na ereasi awy to do tsh,i btu it oerkwd for .me

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thechillhill oS pynpraealt I tdn'o nwko owh to faromt veyr .ellw rS!yro +1

pakimd oS euabsce i ulcntdo pdesn eomr tahn a tuimen no sith nsoeiuqt and eylnthos ndtid rlacel hte d-nbrHaeWygrei aietqonu tsih is hwo i ovelds it redun a tuone:m is ouy nokw ni a vgine atnopolipu hfla of meht lwil be rrarcsie sceni sit an omtuaslao sveisreec aeisdes Aa =aA AA aa Aa Aaso of taht alfh 0%8 aer eud ot tledione tinosuamt dan 0%2 ear edu optni bm niaytusot htat ogilc 08% fo hlaf tino 0%2 of aflh wlil vegi uyo 51/2 +1

draykid 0.8 x .05 is 40. +

topgunber thea isth ewhlo erscmbal :higtn nI eno iel:n 2 * q * h 8T.si%0 is rfo daedssei nisivluddia (wto q lles)Ia.le = 01/106 = q2e^Th qenefrycu fo q = w4o/N0 1 arirscer is 2 p .q P si eclso to noe missnagu WH mqe 1)(qp.+= hsTre'e na oaaitldnid ptse in tshi nsqtoieu due to eth owt riftendfe tsosanot uim. (2q) = 2.10/ %80 of shtee rcarreis aer idntsleeo os llitypum /021 * .08 = /125 +

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