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Retired NBME 23 Answers

nbme23/Block 3/Question#37 (reveal difficulty score)
A 48-year-old man is referred for evaluation ...
108 to 118 ๐Ÿ” / ๐Ÿ“บ / ๐ŸŒณ / ๐Ÿ“–
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 +13  upvote downvote
submitted by โˆ—humble_station(85)
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oS a prslemi ayw ahtn lla hte ahtm binge deon si tnudsgniraden wath CI nms.ae

IC - negar fo evlsua iwn/ hhwic hte teru enam fo teh oiplpoantu si ectxpede afll

oS a IC of 59% will eb more seecrpi nda ahve a rnawro garne codemrpa to a CI of %99 liwl eb less psecire bcaeeus sti cnngiildu mreo usvael ni adn eltrsu ni a diewr .eangr

So fi CI fo %59 is 011 to 161 nhet a CI fo 99% sha ot eb a gnrea atht is .wrid.e. 018 to 181

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paulkarr  alGd I w'atsn eth noly noe ot olsve it tsih dd.iatyn..'w veen tkhni ot borteh ihtw hte lloacic.tuan +2
cagri  I do ont hiktn %95 is orem ereiscp acusebe IC si bslyaacil ngear fo nema suealv htat teepdxec to xesit in an timnr.exepe sThu 99% IC olhdsu eb etrgera aecseub ehhgir IC eanms htat 'I' m nwnedigi my soientxeaptc so my rtcdopeiin is orme lkeliy ot nlovvei ehrto iehghr or smellra .nr'ubems' +



 +7  upvote downvote
submitted by โˆ—sajaqua1(607)
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A dsrandat oidvatnei si a esermua of ypilribotab in nimersblge eht .aeaverg neO danatsrd dtioaneiv no a lebl uvcre tidirntsiuob eracset a 7%6 haeccn ttah teh resnwa iwll iel ni herte. oTw nasdadtr nsviodteai wlil erceat a %59 nache.c ereTh datdnars esaitidonv etaserc a 9%97. n.ccahe

hTis iaepttn sha na raveage of 3,11 dna a 59% nfdenicoec ta -116101 nseam taht teh DS is 51. . oS neo tdniiaolad SD udwol gvie us a eganr of 0.781,-.1551 nodrdeu ot 1811-80.

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usmleuser007  How did ouy etg the SD to eb 5?.1 +
usmleuser007  NMV Got it +1
jesusisking  uoY dtl'wnuo eus dardSnta eorrr htwi ncodeeinfC lenIvr?at pg(. 622 AF )0921 +



 +3  upvote downvote
submitted by โˆ—usmleuser007(464)
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MNV tog .it

tusJ thYF :eI IC swa teadst to be fmro 1-11160 thwi 5%9 dna mnae fo 3 ,o.1S1 no ehrite there rae owt SD no hitree sside fo 131 h(et em)an htta gevi the %5.9

-31=1161 3 winith DS2 voeba teh nema 1110 -=31 3 ihtwin DS2 lwebo teh enam

3 videdid by eth 2 SD = 15. epr .SD

to tge mfor 9%5 ot %99 yuo vhae to rrctenopaio eno orem SD 3( D)S no htreei diess fo eht eanm (311)

rroeTe;efh at 99% CI 15=011.- 5180. IC 1+1=.516 7115.

dRonu hseet pu and oyu etg 18180-1

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tyrionwill  %59CI = M ยฑ SZE)( dteiasn fo 16- 111D3S = 3 wihnit E,S2 otn DS SE2 = tcaDrtxeS/ eht easqur roto fo n = /2SD dna SD = S2E +
tyrionwill  ryoSr I meda a s,iamket enctegl het aebob +
tyrionwill  fi uoy esu naeM ยฑ SD2 = IC59% to nowk ,DS tehn ues nMae ยฑ D3S to ynol wkon C97.,I%9 a tbi grelar htan 99CI% +



 +3  upvote downvote
submitted by brainchild(3)
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orF all hte hm~a~t oleppe out :rehe

IC = enam + Z(E)S

rFo a 9%5 IC, Z = 9..61 orF a 99% ,IC Z = .85.2

Teh CI is 3+/-3 from the m,ean os 3 = (96E1)S. twih the 95% .CI evoSl rfo ES hi(cwh 'oetdns cgehan if yuo ghcena hte )C,I whhci ocsme out to tuboa 3..51

Now cshtiw up teh Z uealv rfo the 9%9 ,IC ihwt eth ES you sjut datlalc.uce IC = 825. * .153 = .39.5 dAd sthi ot htob seisd fo the mane ,311() dan ouy tge hte nsewra!

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lulumomovicky  I did alcetyx teh ameeese +



 -1  upvote downvote
submitted by โˆ—drmohandes(193)
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I terdi to cceuaaltl it orem ie,psrec and sesdem pu het wn.ase.r.

Heer si hy:w

  • %99.7 IC = 3 SD
  • eerov:Hw 9%09. CI is uylcatla 5.2 SD (ro 2.57 if oyu wnta to be emor risee)pc

1 DS = 51. gmHm โ†’ .52 DS = 57.3 mGmH

sTih sertuls ni a 9%9 IC fo 192.50 -3(1175.3) to 15.671 3(7+13)51.

Celsro to wnrsae C naht .B

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