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NBME 24 Answers

nbme24/Block 2/Question#50 (26.5 difficulty score)
An obese 57-year-old man comes to the ...
Normal ciliated columnar epithelium replaced by normal squamous epithelium🔍

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 +5  upvote downvote
submitted by lsmarshall(345),
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isMaeapatl - A revisbeler pvadatie esenorsp in cwhhi hreet is rgmpanRrg"oiem of tmes arelmcŽlpenltcees fo one llec yetp by rneahto taht acn dptaa ot a wen "t.sessr ohtB rae rlnaom Roerrtpiysa eert shdulo ont aevh ssqumoau lcesl ntilu rtseprryioa lnchboesroi e(bofer t;aht oadlicbu in rte.m obn.r &g;t uocnrmla ni ob.chrn &t;g apiredosefsutidt unocmarl in l.aerg .crbh)o.n

shayan  if its a metaplasia, then how it be normal ? I mean Metaplasia is not normal? +1  
artist90  i got it confused bc the question stated that there was a mass in one lobe of lung and i didn't knew that squamous metaplasia also presents as a mass in lung. i missed that on biopsy they were clearly stating squamous metaplasia. +4  
suckitnbme  @shayan The term "normal" in the answer is used to indicate that the cells appear normal (meaning appropriate size/architecture/appearance). Remember that metaplasia is a normal response to stress. +4  

they said "metaplasia"

Metaplasia= normal tissue but in an abnormal place classic example- Barrett's its NORMAL mucousa for the stomach, but in the esophagus.

metaplasia - (as i learned its definition to be) - defined as replacement of one mature/normal epithelium with another mature/epithelium that is better well suited to handle stress.

thisshouldbefree  also dont forget metaplasia and even dysplasia are still reversible +  

 -2  upvote downvote
submitted by krewfoo99(76),

This could easily be confused with Squamous Cell Carcinoma as they are describing a mass. But i think the key difference is that they mention METAPLASIA. If it was dysplasia, then it would have been cancer.

usmlecrasherss  metaplasia also can lead to cancer FA p206 2019 +  
suckitnbme  Dysplasia is not cancer since it is, in theory, still reversible. Only when it becomes irreversible is it a carcinoma. +1