charcot_bouchard
Wtha fi i lelt uoy iths is a sueq of aAltuttierbb ksri % in epoxs?ed R=A
.020 / IR in deoxeps 13000/)(0 = 7
36.6006 csae ni 1.000 So 003 sace in 6,.0
10000676 x 300 = 002 or ni renotah dwro 6%6 esacs of 001 lgun aecrcn saesc in resmsok is uctlayal edu ot kogsnim. so ni 003 ssaec of ersksmo 020 si laayltcu eud to oknisgm
+5
charcot_bouchard
hsTi is a idmn k.ufc mLeem tlle u usyg fi any nitonoasolc wlhie iongd eth seuq niurgd stte i ddi it twih AR = 0;.20 NNH = 1002./ = .50 50 nossrep ekosm to ceusa 1 rc.aenc K01 ksome to uacse 200 ecrcn.a
+4
ls3076
yrroS fi isth si a dtupis instoue.q yWh is it iocrntcre ot mspliy aplyp teh emsa irrpopotno 3(0 aneccr erp 1000 skeomr)s to 0000,1 rsmsko?e
+2
krewfoo99
@360i7s Tahst ctyaexl tahw is ddi. I tlisl tdon rdnesuantd ohw atth is rnogw. But i gusse yhte wnta su to ntkih buota ti in rsetm fo RA
+1
hhsuperhigh
I376s0@ nad o9@,9rwKofe If a oernps dt'eosn skm,oe het aaulrnt irks of teiggnt lgun cnarec is /31%0=0.300 heT moksesr' rksi si 1%.00/3=300 hTis %3 is ton rueylp ntoidrbtuec by ,gmoknis but iedmx htwi teh aurlnta sirk. So rof acntlaulgic het urep cnooritniubt aedm yb ,gkmsoni uyo douslh use 3%-%1 hihwc is %.2 dAn tsih 2% is teh rpue nnribotcouti fo ns.goimk Nto lal eossrmk teg glnu anecc,r het saem ngtih, ton lla gnul rencac mngao mroesks era eurbdtttai yb osg.mkin eTyh yam tge gnul rancce ywnaay tsdepei isokmng or .nto
+21
submitted by โcolonelred_(124)
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$279$49ttAbiealtrub riks = cnceidein in ospxeed โ eiecdnnic ni sneoxedup
= 0010/0,3
ks(s)rmeo- ,30/0300
rnso)em(skno= .030 - .010
= 0.20
os( eth ublttiretbaa isrk si oabtu 2%)pylgpiAn it ot a ipatuoonlp fo 0,0:001
= .020 * 10,000
= 020
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