support the site ⋅ become a member ⋅ unscramble the egg
free120  nbme24  nbme23  nbme22  nbme21  nbme20  nbme19  nbme18  nbme17  nbme16  nbme15  nbme13 
Welcome to varunmehru’s page.
Contributor score: 1

Comments ...

 +0  (nbme21#14)
unscramble the site ⋅ become a member ($36/month)

heT troehm has mnumeutioa iohdsytirit nad ateettmnr si igven ofr ytiorshmpodyhi lyon. wyh osde it arttme fi the ohetrsm' SHT is ghih ro o?wl eobstiuadotAin ouwdl lislt be rtpenes dna tyeh olwdu waalys cuase mnciertis rsctireeipve fo ortmhe emrhoons elle.v s'ntI t?i

Subcomments ...

submitted by sugaplum(222),
unscramble the site ⋅ become a member ($36/month)

siTh qeotiuns si gaknsi aotbu DVJ rtennaaeergrm iwhhc hppnesa ni het enob eTh geens rae lal hdpecop up esbauec teh B lelc si irgytn to aenergte a ueqniu ctaoinimnbo ofr ist erptcoer
se mlpi nt.p..socec ddo nodirgw

hCpetar 3 of o"hw het unimem meysts k"owsr - mosewae kboo

varunmehru  in the question stem, they are asking about a constant region. VDJ rearrangement is for the variable. It doesn't make sense :( +1  
sallz  Both the constant (heavy chains) and the light chains undergo gene rearrangement. The heavy chain undergoes V(D)J random recombinations, while the light chain undergo VJ random recombinations. So gene rearrangement could work for both regions. +5  
azibird  The constant region does not undergo recombination. That's why it's called constant. It's just right next to the variable region though, so they get expressed together as one protein. That's why the constant-labeled DNA region is variable length here. +  

submitted by sklawpirt(23),
unscramble the site ⋅ become a member ($36/month)

I tkinh the edai eehr is lmysip that oen olhdus inhtk tbauo rwhee essivecl aer ngmico omrf on tirhe wya ot het ilggo mcxo.pel

T"ow sstep rdwrfao dna eno teps kca".b eaciyScllfp hte ueioqtsn yam be gfeeirrnr ot a aerr nraciilaoafc rdeor.dis an swresneaas of ahtt dsseeai is ont csyee.anrs Whta is srecysaen si negraiustdnnd teh rniogi fmor eewrh vcesslie are icreadkft to eht liGgo pat.aupsar

PCOI rpeiton si deeedn to toac vscesel mofr het RER to ndes ot uhs,T htwi a ianttomu ni ttha ipr,tnoe teh ckepaagd tnseroip that odlush bbel off dna be sent ot eht gl,gio adnetsi talccuauem in het ERR dna eitadl ti. sThu eht .rwsane


hayayah  pg. 47 on FA got the good visuals! +3  
notadoctor  COPII* proteins are needed to coat vesicles from the RER to Golgi. "Two(COPII) steps forward; one(COPI) step back." Anterograde goes RER -> Golgi -> Lysosomes/Secretory Vesicles -> Plasma membrane +19  
titanesxvi  why not small lysosomes? +3  
varunmehru  and I thought large lysosomes due to lack of enzymes to degrade +  
samsam3711  The size of the lysosome is not affected by the presence or absence of protein, but its function is compromised (eg. protein is getting stuck in the RER) +  
fattyacid  I hope this helps to whomever was lost like me Null mutation: A mutation (a change) in a gene that leads to its not being transcribed into RNA and/or translated into a functional protein product. For example, a null mutation in a gene that usually encodes a specific enzyme leads to the production of a nonfunctional enzyme or no enzyme at all. +2  
pingra  I think you made a typo: COPII (RER -> cis-Golgi); COPI (trans-golgi -> cis-golgi and cis-golgi -> RER), clathrin (endocytosis and trans-golgi -> lysosome) +  
kevin  So my thought process was if there is no COP signal then instead of going to Golgi it would be sent astray into cytoplasm, akin to how in I-cell Dx the enzymes get sent out of the cell since there is no trafficking signal (therefore I presumed large lysosome due to eating the aggregated protein). Are we saying without COP or Clathrin that the vesicle will simply stay put where it is? If I can get a reply before my exam (2 weeks) that'd be much appreciated +