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Retired NBME 24 Answers

nbme24/Block 4/Question#14 (reveal difficulty score)
A new screening test for colon cancer is done ...
118/124 = 95% ๐Ÿ” / ๐Ÿ“บ / ๐ŸŒณ / ๐Ÿ“–
tags: biostats

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submitted by โˆ—m-ice(370)
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iciiStypcfe is qulea to het nmbrue fo teur eignvtae ttses over teh renmub of teru setvinaeg lpsu safle ve:tipossi

cSpe = TN (/NT + FP)

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submitted by โˆ—avicenna(12)
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sutJ in sace mneseoo esedn a e yvewisviittienSr si tcdaalluec yb ddgivnii teh nmreub of teru ptoss,iiev yb the otlta enrumb of lla epolpe how eahv hte ntdnioioc - the erut peosivtsi nda saelf ev.iegtsna

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