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nbme23/Block 4/Question#8

A 36-year-old nulligravid woman and her 40-year-old ...

1 of 50

+4  upvote downvote
submitted by seagull(714),

Hardy-Weinberg equation = 1= P^2 + 2pq + q^2

P^2 = 1/10,000 = 1/100

Then remember P + q = 1 ------> 1/100 + q = 1 (q = 99/100)

Lastly plug back into Hardy-Weinberg Equation as:

2pq = Heterozygote carrier

(2 x 1/100 x 99/100 = 2/100 = 1/50)

link981  I think q should be 1/100. You got p and q mixed up. +2
humble_station  Because p = 99/100, you can just make it 1. Then just do 2 x (1/100) and you get 1/50 +3
humble_station  Because p = 99/100, you can just make it 1. Then just do 2 x (1/100) and you get 1/50 +
unhappy_triad  Carrier frequency= 2pq AR disorder that occurs in 1 in 10,000 the square root of 10,000 is 100 so, q=1/100=0.01, p= a number close to 1, just use 1. plug it in the equation 2pq= 2(1)(0.01)=0.02=1/50 +1

+2  upvote downvote
submitted by tamey(0),

disease prevalence is 1/10000 which means q square=1/10000 thus q=1/100 and since they are asking about carrier frequency which is 2pq, p is always assumed 1 this will lead to 211/100=1/50