lotat ccnroionnetat = /.003mlg x 0L02 = h6ge0 m otko het gdru 6 urohs oag @ tlfa-h fo 2 ru0sm0o= 1=g2oh24hg g=s8mh0=rsr64u g=hs =oomsh6r0=4m02ru=u
Q46: half life (2 hrs) is the time it take for the drug concentration to half. Since the time course is 6 hours after injection, 3 half-lives have passed. The concentration 3 half-lives later is 0.3 mg/L. This means at the time of injection, the concentration should be 0.3x2x2x2 = 2.4 mg/L. Utilizing the formula mass/volume = concentration, mass (what the question is asking) = volume x concentration = 200L x 2.4 mg/L = 480 mg.