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NBME 23 Answers

nbme23/Block 4/Question#16 (reveal difficulty score)
In a study of the use of ultrasonography for ...
80% ๐Ÿ” / ๐Ÿ“บ / ๐ŸŒณ / ๐Ÿ“–
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 +6  upvote downvote
submitted by โˆ—yb_26(315)
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oanlmabr tste eslrtu msean tath estt dcsetet arccne &;=gt

  • 35 fo 05 nme ihwt trtosape crnace ahve moabnarl test tserul =&;gt n of stp thwi rnacce = 5.0 estT oshws cacern in 53 nme g;t=& =5PT3 ;g&t= ew nca ceacatull NF = 03-55 = 51

  • 02 of 100 nme itotwhu eaortspt ccrnae ahev bmlorana ttse relstus t&g;= FP 02= t&g;= ew can cctlaauel NT = 0082=001-

  • won we anc alteclacu scycietfpii = TNNP+(/)TF = 08010/ = .08 i(n % lwli eb )0%8

rhee is my 44/ lb:ate [ ectdines23lwm_s/s.ioupqee_ct/wcupo/btm3otdsw/tm1ts/otub.rc:nho_m/e/am/mtinwlrrefs]

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smc213  Eylxtac athw I idd! +
smc213  I lgdegoo eht mienang of lraomabn tets selutrs jsut to make .rues A tvipeois sett is neo ni chwhi het erltsu of het sett si aon;rmalb a gatienev test si one ni whcih the t'ests leutsr si .aolnrm +4

This guy on youtube does a killer job on explaining all these problems. Just does problem after problem on 2x2 tables and a few other topics. The link to part 1 is added, part two you can find on the side panel I'm sure. Part 1

+1/- paulkarr(73)


 +1  upvote downvote
submitted by โˆ—meningitis(643)
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ehT nteuqiso is cifnosngu uaeebcs a RUTE EISTPVIO ttse slrute si fdnigin eittengcd nrceac yb SU ogs(e to sowh yuo ew atgto okol ta twah het stte si ognokli r.of)

An BONRMAAL etst etiegtndc aCrP snmae ist NTO A PVII:STEO e:i 53 uot fo 05 wree laFse Pvioesits

An RAAOMNLB etst TTOHWUI CraP aenms sti OTN A GA:EVTEIN 02 uot of 100 IHUOWTT aCrP wree ELFAS IENV.ATGE

NT = 08, PF = pc:tS15ye ifc.ii FTT/;(N)+NP 58/080+()1 = 4.8An%d ensci it ssay etsb" nptees"rers then %84 is seoclts to %.80

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 +0  upvote downvote
submitted by โˆ—lfsuarez(160)
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02 fo teh 010 emn uhiotwt orsaptet eaccrn evah nmraalob ttes ssuertl.

iicpiSfycte = PFNP/T+F = /20100 = .80 = 8%0

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seagull  l.amtso 20 1 / 0 01 = 83% guorlhy 08% +
amirmullick3  tNo eusr ahtw lfsaezru nad uglales aboev .naem reeH is ym iec.ncaSeioltfitpp xnayi = PNT+F./N(T) ihTs stet aveg 20 safle ovistiesp uto fo 001 plopee, dan nylo 15 treu envegstia uto of 50 miytiepeSif. ncc osal esauql ,-t1PrFea nda hree het PF tear meses 02% so %0-8012=%.00% +4
yb_26  nmaarbol etts rtleus snmae tp ash nrecca tg&= ;TP = ,35 NF = 51 -350,5)( ,=F02P NT 0=8 (0-201)0 t=&;g ciypiiesfct = (NPF/TTN+) = 01/080 = .80 (in % iwll be 8et0 r)%u aistgnvee are 80 out of 100, ont 51 otu fo 05 +2
bulgaine  fI oyu rceleap the usvael orfm hte ietouqns ni the labet of pgae 725 of FA ,0129 _26yb txealapionn si tcerorc. noaArmlb stte = ipttane ash canerc = estt u tosQe+in yssa 3505/ nme htwi ospetrat crneca (so all 05 vhea a)necrc ynol 35 avhe ramlnbao tets sultes,r amngnie tath =3TP5 ieeass(d + etst +) nad N=F 15 iess(eda + estt - suaecbe eyth od aehv cecrna tbu eht etst was not maabolrn for hmte .) 02 0/10 nem wotuhti petaotrs cracne veha onramlab stet etrussl naminge lla 100 NDTO aveh enracc ubt 02 sohw hatt they vaeh ccerna whne its ton rteu so 0FP2= ids(aees - etts +) dna TN =08 siesa(de - stte )- +



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