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Retired
NBME Answer
Explanations
Welcome to tatianalimo’s page.
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q= 1/100.000 (frequency in males) p+q=1 2pq=? (frequency of heterozygous)
2pq=0,00002=1/50.000
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q= 1/100.000 (frequency in males) p+q=1 2pq=? (frequency of heterozygous)
2pq=0,00002=1/50.000