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submitted by sajaqua1(519),
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HMC I ifucnnto is girenatl ot eccnar ssnoeuispr.p CMH I ydpilssa dgnyouleneos sesyiheztnd oirpestn and ntesprse ethm ot +D8C T .sllec heT feluira to diylpsa CHM ,I or HMC I ldapiys of son-enlf nd(a yb neinotxes erocausnc) rietpsno retsggir a lalluecr imemnu e,rssoepn inedlga ot dotsirecunt fo hte lecl.

The pseeoatorm si sdeu rof het ngaoeidtadr of norw u,ot enncetsse, ro mfamelodr ioentr.sp sA enrcca o,dvepesl rmoe ntauotmsi edal to neaiesdcr norgw er.tsopin Only yb nepsxeoirs of het po,osrateem or tsi xe,rpo-ovesersin acn eesht tatumn riespnot eb eerdagdd fsat ueghon to nto be yeasdpdli yb CHM I nad ldea ot het clel igenb dil.lek zbtrBemioo slkcob het a,eptsmoore so the uatmtn onrpeist rea ydielpsda on the u,rasefc nlwoagil hte imemun teyssm ot nozcgeeir dna lkli gihacloloapt lcle.s

catch-22  Another way to approach it is to think about MHC class I processing. Basically, if you inhibit the proteasome, peptides will not be generated and nothing is available to be loaded onto MHC I (remember MHC I has to be loaded before it's transported to the cell surface). Cells that don't express MHC I get killed by the natural killers. +25  
kai  "In conclusion, we have demonstrated that the proteasome inhibitor bortezomib down-regulates class I and enhances the sensitivity of myeloma to NK cell–mediated lysis" from the conclusion of the NIH paper +5  
maddy1994  another mechanism is by blocking proteosome u even decrease degration of proapoptotic it enchances apoptosis(from uworld) +3  
azibird  But CD8+ and NK cells kill via perforin! Why is this answer wrong? Is it because it's not the primary effect? +2  
testready  "The proteasome is the major source of proteolytic activity involved in the generation of peptides for presentation by major histocompatibility complex class I molecules. We report the new observation that bortezomib down-regulates HLA class I on MM cells, resulting in increased NK cell–mediated lysis." +  

submitted by hayayah(1056),
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maColboo is na eye rmnabaotliy that corusc ebroef rith.b ey'Tehr igmsnis epesic fo siteus ni ucttresrsu atht ormf teh .yee

  • smlooCboa fectagfin the s,rii hiwch erstul ni a "eyoekl"h aaecpperan fo hte pupil, rgyllenea od not dlae to soniiv lsos.

  • molsbaooC inigvvonl het eirant srulet in sinivo olss in iifcspec pasrt of eth lvuisa ld.fei

  • gaLer ntleari msloooabc or soteh ftengcfai eth ctipo rneev can aescu wlo voniis, ihwhc measn sioniv ossl atth nncota eb epleoytmcl rtdreecoc ithw algsess ro aocttnc n.elses

mousie  thanks for this explanation! +  
macrohphage95  can any one explain to me why not lens ? +  
krewfoo99  @macrophage95 Lens are an interal part of the refractive power of the eye. Without the lens the image would not be formed on the retina, thus leading to visual loss +4  
qfever  Do anyone know why not choroid? +1  
adong  @qfever, no choroid would also be more detrimental to vision since it supplies blood to the retina +2  
irgunner  That random zanki card with colobomas associated with a failure of the choroid fissure to close messed me up +11  
mnemonicsfordayz  Seems like the key to this question is in what is omitted from the question stem: there is no mention of vision loss. If we assume there is no vision loss, then we can eliminate things associated with visual acuity (weird to think of in 2 week old but whatever): C, D, E, F. Also, by @hayayah 's reasoning, we eliminate E & F. If you reconsider the "asymmetric left pupil" then the only likely answer between A & B is B, Iris because the iris' central opening forms the pupil. I mistakenly put A because I was thinking of the choroid fissure and I read the question incorrectly - but it's a poorly worded question IMO. +  
mamed  Key here is that it doesn't affect vision- the only thing would be the iris. All others are used in vision. Don't have to know what a coloboma actually is. +2  
azibird  The extra section of that Zanki card specifically says that a coloboma "can be seen in the iris, retina, choroid, or optic disc." Don't you dare talk trash about Zanki! +1