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Welcome to karljeon’s page.
Contributor score: 89


Comments ...

 +6  (nbme24#15)
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I 'todn wonk fi rehet is na nituqeao ofr ist,h ubt I clayiblsa pedupm otu veyer ivdosini rssaoc teh ltaeb ot get ~5% on g.vreeaa

Heer yeht 4a: 00er / ,6000 = 60.7 5002 / 00,65 = 00540 .03 / 35,05 = 30 .00056 / 005,5 = 0290. 505 / 8,400 = 0250.

heT evaegra fo ehste %s rof lal hte asery = .o5 8.S5% tthsa' ocels hegnuo to %.5

seagull  good work. I found this question annoying and gave up doing those considering the amount of time we are given. +4
vshummy  Well just don’t include the intake year... because that messed me up.. +11
_yeetmasterflex  How would we have known not to include the intake year? From average **annual** incidence? +
lamhtu  Do not include intake year because the question stem is asking average annual incidence. The 4000 positives at intake could have acquired HIV whenever, not just in the last year. +5
neels11  literally didn't think there was an actual way to figure this out. but my thought process was: okay incidence means NEW cases. so the annual average at the end of 5 years would be: (# of NEW people that tested positive at the end of year 5) / (# of people at that were at risk at the beginning of year 5) <--- aka at the end of year 4 250/5050 = 4.95% also if you look at year 5: you'll see that the at risk population is 4800 when 300 new cases were found the year before. 5050 at the end of year 4 MINUS the 300 new cases at the end of year 4 should give you 4750 as the new population at risk. but notice that end of year 5 we have 4800. idk if that means 50 people were false positives before or 50 people were added but in incidence births/death/etc don't matter it's kind of like UWORLD ID 1270. assuming average annual incidence is the same as cumulative incidence this was just a bunch of word vomit. sorry if it was unbearable to follow +

 +7  (nbme24#23)
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A nam wiht a xH of EtOH depceedenn adn cricnho dab apni sa llwe sa raXy- ndnfsgii fo atciclfc"oinias ni het updmpe-ir obde"nma si msto leykli ieerrgrfn ot a crihnco atsiip.raentc

hiTs sdlae ot a lack fo saelip tseiercno nche,e e,pla llngumf-oslie osotsl tihw ilo rlspedot pre tp Hx. ihTs t'sp nepaacsr aols tesond' etecrse throe ezesyn,m hcus as ayss,mlae te,osparse nor spngrnyotie ot( vtaceait treoh smn)yez,e so het resnwa si gnaler"zeied .oartpal"iobmns

karljeon  p. 367 (FA 2018) +6
usmlecrasherss  pancreatic insufficiency FA 2019 p375 , +1
almondbreeze  FA 2019 p391 on chronic pancreatitis +
almondbreeze  UW: in chronic alcoholic pancreatitis, alcohol induced secretion of protein rich fluid precipitates in pancreatic duct--> forms ductal plugs that calcify +2

 +14  (nbme20#2)
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hsiT oen wsa a wheastom speilm ioeusntq nscei tpcoehameyhr &tg--; omutr slisy &tg;-- ndee einxhnat xodseai ibtirhnio e,(g ustxo.)fabet

TBU WYH IS NMEB RAAMGRM OS CAR?P UTP UYRO MCSAOM IN ETH TIHGR CLA!PE

malou  I swear I registered just to upvote your comment. #SoFrustratedToo +
xoxofossagirl  ,omg, me, too, , +

 +4  (nbme24#23)
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mntiVai E efndicciey sueacs metolichy inea,am ootcihy,tsaansc lumsce asken,esw ireropsto lmncou adn enoeeilabrlsprc rcatt neim.dtaonyeli

karljeon  Can anyone explain why the serum lactate dehydrogenase (LDH) level was elevated? +
asapdoc  Vitamin E is an antioxidant. Thus a deficiency can cause hemolytic anemia. +5
sympathetikey  @karljeon Intravascular hemolysis = LDH release from RBCs +1




Subcomments ...

submitted by karljeon(89),
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A nma twhi a xH of tEOH eepnededcn nad irchcno adb iapn sa elwl as -aryX dgnfnisi of claccnisftai"io in het um-pdeirp naedbom" is smot lliyek rfrregnie ot a cocihnr priac.asietnt

hTis seadl to a aklc of seaipl inoreects e,chen pla,e nl-sleflmiugo tolsos ihtw ilo odreltps pre tp Hx. ishT s'pt seacaprn laso sd'ntoe ecetser oehtr mes,eyzn csuh sa sesaymla, ro,eapstse rno ipoeygtnrsn to( evicaatt teroh enyz)e,ms so eth rwanse si zieglaen"red mo"iaalsnrt.opb

karljeon  p. 367 (FA 2018) +6  
usmlecrasherss  pancreatic insufficiency FA 2019 p375 , +1  
almondbreeze  FA 2019 p391 on chronic pancreatitis +  
almondbreeze  UW: in chronic alcoholic pancreatitis, alcohol induced secretion of protein rich fluid precipitates in pancreatic duct--> forms ductal plugs that calcify +2  


submitted by strugglebus(154),
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I ohces ihts elosly bsecaue it was os damn iifecscp

sympathetikey  Same. Learn something new every day: See more: https://www.fda.gov/safety/medwatch-fda-safety-information-and-adverse-event-reporting-program +4  
karljeon  I didn't choose it because it was so damn specific. :( +28  


submitted by strugglebus(154),
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As an 1e1ti00 ,0d:8 poeple tproedre ot veah desi efcefst hwen nkaigt lHdocm.izrhth raoonidgeoAy htme, 52 epelpo %0()0.2 aevh Baerts hsiceardg

neonem  I think the best way to answer this question was by process of elimination. +1  
sympathetikey  That's some bullshit lol +4  
karljeon  Haha I eliminated the answer by process of elimination. +18  
medschul  I eliminated thiazides by process of elimination :( +1  
medstudent65  Shit I eliminated thiazides because of elimination went with HTN thinking intercranial bleed effecting the pituitary +1  


submitted by hayayah(990),
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N,ecito teh esmt yssa p"crreoossr in hte iksn"

D3 e)(hoecrlclaflcoi rfmo reupxseo of nkis ttr(smua )alaebs ot sun, otigienns of hsf,i il,mk ptns.al

2D alf)ro(gloirecce rfmo nioetsnig fo lptsan, fnug,i stays.e

tBoh dtevrnoce ot 2O5H- D3 ao(sretg fo)rm ni vreli nda ot hte civaet fomr (25H)1,-2O 3D rtcio)acl(li ni ykeni.d

sympathetikey  C is the 3rd letter in the alphabet. Hence, D3 = Cholecalciferol +4  
karljeon  Thanks for the explanation. The question stem made it sound like "what future step will be decreased?" Actual question: "Decreased production of which... is most LIKELY TO OCCUR in this patient?" Maybe NBME needs a grammar Nazi working for them. +6  
bharatpillai  question says "decreased production of which of the following precursors in skin is most likely to occur in this patient? the answer has to be 7-dehydrocholecalciferol! +3  
bharatpillai  7 dehydrocholesterol +2  
brbwhat  Yeah i did the same, but then realised acc to uw flowchart 7dehydrochole.. is converted to cholecalciferol in presence of uv rays. So the decreased precursor would be cholecalciferol since we already have 7 dehydrocholecalciferol not being converted by uvrays Tho the uw chart sites both ergo and chole as dietary sources. +2  
drzed  Wouldn't 7-dehydrocholesterol build up in the skin? Since UV rays convert 7-dehydrocholesterol into cholecalciferol, if you are lacking the conversion, the reactant (7-dehydrocholesterol) should accumulate. +  
brbwhat  They’re asking decreased production of which of the following precursor would occur? 7 dehydrocholestrol builds up, but decreased production of cholecalciferol takes place, which is a precursor in the pathway for vitamin d formation +1  


submitted by karljeon(89),
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atiVimn E nyeecicifd csasue mihlctoey n,amiea ,yaisotoaccnhts seclmu swn,eakes opteirsro omnclu nad nebioplelrceras trtca .ldteaieminnyo

karljeon  Can anyone explain why the serum lactate dehydrogenase (LDH) level was elevated? +  
asapdoc  Vitamin E is an antioxidant. Thus a deficiency can cause hemolytic anemia. +5  
sympathetikey  @karljeon Intravascular hemolysis = LDH release from RBCs +1